Given that the probability <span>is
modeled by the function
![y=3(257,959)^x[tex] where x is the impurity concentration and y, given as a percent, is the probability of the fuse malfunctioning.\\Then, the probability of the fuse malfunctioning for an impurity concentration of 0.17 is given by [tex]y=3(257,959)^{0.17}=3(8.316941)=24.95](https://tex.z-dn.net/?f=y%3D3%28257%2C959%29%5Ex%5Btex%5D%20%20where%20x%20is%20the%20impurity%20%0Aconcentration%20and%20y%2C%20given%20as%20a%20percent%2C%20is%20the%20probability%20of%20the%20fuse%20%0Amalfunctioning.%5C%5CThen%2C%20the%20%3C%2Fspan%3Eprobability%20of%20the%20fuse%20malfunctioning%20for%20an%20impurity%20concentration%20of%200.17%20is%20given%20by%20%5Btex%5Dy%3D3%28257%2C959%29%5E%7B0.17%7D%3D3%288.316941%29%3D24.95)
Therefore, the <span>probability of the fuse malfunctioning for an impurity concentration of 0.17 is 25% to the nearest percent.</span>
</span>
The answer is 112 on the number line
Answer:
5/8
Step-by-step explanation:
We have to present the number 41 as the sum of two squares of consecutive positive integers.
1² = 1
2² = 4
3² = 9
4² = 16
5² = 25
16 + 25 = 41
<h3>Answer: 4 and 5</h3>
Other method:
n, n + 1 - two consecutive positive integers
The equation:
n² + (n + 1)² = 41 <em>use (a + b)² = a² + 2ab + b²</em>
n² + n² + 2(n)(1) + 1² = 41
2n² + 2n + 1 = 41 <em>subtract 41 from both sides</em>
2n² + 2n - 40 = 0 <em>divide both sides by 2</em>
n² + n - 20 = 0
n² + 5n - 4n - 20= 0
n(n + 5) - 4(n + 5) = 0
(n + 5)(n - 4) = 0 ↔ n + 5 = 0 ∨ n - 4 =0
n = -5 < 0 ∨ n = 4 >0
n = 4
n + 1 = 4 + 1 = 5
<h3>Answer: 4 and 5.</h3>
