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Olenka [21]
3 years ago
6

Solve the equation 2x - 3 plus 4x = 21

Mathematics
1 answer:
vichka [17]3 years ago
4 0

Answer:

x=3

Step-by-step explanation:

Add like terms and get x by itself.

2x-3+4x=21\\6x-3=21\\6x=18\\x=3

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Someone who creates new ideas for profit is called
Airida [17]
The correct answer is D. An Entrepreneur.

I hope this helps. :)

And have a great day.
7 0
3 years ago
2x^2-7x=-1 what are the solutions in decimal form?
Scorpion4ik [409]
0.14921894<span>3 or 3.3507811

Hope this helps!!
</span>
8 0
3 years ago
HELP PLEASE
Georgia [21]

Answer:

\huge\boxed{\sf No}

Step-by-step explanation:

Evan spent 20 hours doing homework last week

25 hours were spent this week.

<u>Let's see what 125% of 20 equals:</u>

= (125 / 100) * 20

= (125 / 10) * 2

= 125 / 5

= 25 hours

But,

<u>It is written that Evan thought he spent 125 % more than the last week which means:</u>

= (125% of 20) + 20

= 25 + 20

= 45 hours

He should've said that he has given 25% more time than the last week.

(<u>Note that:</u> 25 % of 20 equals 5 so 25 % more than last week will be equal to (25 % + 20) = (5+20) = 25)

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
7 0
3 years ago
A manager is comparing wait times for customers in a coffee shop based on which employee is
anyanavicka [17]

Using the t-distribution, as we have the standard deviation for the sample, it is found that there is a significant difference between the wait times for the two populations.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if there is no difference, that is:

H_0: \mu_A - \mu_B = 0

At the alternative hypothesis, it is tested if there is difference, that is:

H_1: \mu_A - \mu_B = 0

<h3>What are the mean and the standard error of the distribution of differences?</h3>

For each sample, we have that:

\mu_A = 73, s_A = \frac{2}{\sqrt{100}} = 0.2

\mu_B = 74, s_B = \frac{4}{\sqrt{100}} = 0.4

For the distribution of differences, we have that:

\overline{x} = \mu_A - \mu_B = 73 - 74 = -1

s = \sqrt{s_A^2 + s_B^2} = \sqrt{0.2^2 + 0.4^2} = 0.447

<h3>What is the test statistic?</h3>

It is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{-1 - 0}{0.447}

t = -2.24

<h3>What is the p-value and the decision?</h3>

Considering a one-tailed test, as stated in the exercise, with 100 - 1 = 99 df, using a t-distribution calculator, the p-value is of 0.014.

Since the p-value is less than the significance level of 0.05, it is found that there is a significant difference between the wait times for the two populations.

More can be learned about the t-distribution at brainly.com/question/16313918

8 0
2 years ago
Due tonight please help me
amid [387]

Answer:

k=61, l=61, m58

Step-by-step explanation:

5x+21=2x+45

3x=24

x=8

5 0
3 years ago
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