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2 years ago

HELP PLS!! this is geometry and I’m not sure how to do it!! So I was wondering is someone could help me solve these!!

Mathematics

2 answers:

romanna [79]2 years ago

6 0

Answer:

I couldn't find questions.

You can follow me ask help

victus00 [196]2 years ago

4 0

We cannot see the question please show

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Andrew's math teacher entered the seventh grade students in a math competition there was an enrollment fee of $30 and also an $1

N76 [4]

Answer: 110

Step-by-step explanation:

Given;

Total cost C = $151

Enrollment fee E = $30

Charge per 10 test t = $11

n is the number of packet of test taken.

The questions can be represented by the equation below;

30 + 11n = 151

Substracting 30 from both sides.

11n = 151-30 = 121

n = 121/11

n = 11

Since the number of packet of test is 11 and each packet contains 10 tests. The number of test N is given by;

N = 10 n = 10 ×11 = 110

N = 110

5 0

3 years ago

Mrs.Leitz spent $8.75 on new folders, f, for the 25 students in her class. Which equation shows how to find the cost of each fol

mrs_skeptik [129]

Answer:

each folder costed 0.35

Step-by-step explanation:

8.75 divided by 25 would have given you the answer

8 0

2 years ago

Find the number, if 5/7 of it is 15

Karolina [17]

Hey there! :D

Divide 15 by the numerator so we can find 1/7.

15/5= 3

3*7= 21

The number is 21.

I hope this helps!
~kaikers

7 0

2 years ago

Read 2 more answers

HELP WILL MARK BRAINLIEST TO BEST ANSWER!!!!!!!! I NEED ASAP

Bond [772]

Answer is B

Find perimeter then divide by 3 (because price is per 3 meters) then times by 500 to get the answer

4 0

3 years ago

A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang

laiz [17]

Answer-

a. Probability that three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

Solution-

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

$\binom{19}{3} = \frac{19!}{3!16!} = 969$

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

$\binom{33}{6} = \frac{33!}{6!27!} =1107568$

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

$\binom{52}{9} = \frac{52!}{9!43!} = 3679075400$

∴P(3 white candies) = $\frac{1073233392}{3679075400} =0.29$

Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

$\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}$

$=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})$

$=(969)(45)(7)(5)(15)=22892625$

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

$\binom{52}{9}=\frac{52!}{9!43!} =3679075400$

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

$\frac{22892625}{3679075400} = 0.006$

6 0

3 years ago