Answer:
let cp be x
sp= 115x/100 ---(when 15%gain)
sp = 88x/100------(when 12% loss
according to question
115x/100 - 88x/100 = 81
or, (115x-88x)= 8100
or, 27x = 8100
or, x= 8100/27
x = 300
hence cp is RS 300
The answer of all of this is 18 because 18.1 months so if you do the math you get 18-7x+20^2
Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
Just put them together. The subtraction sign is a negative sign. First step: 8v-10v= -2v Second Step: 8j-6j= 2j So your final answer would be: 2j-2v
