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1 year ago

Can y’all help me with ! I need correct anwsers ! Please

Mathematics

1 answer:

romanna [79]1 year ago

6 0

Answer:

Im pretty sure its B, 1.75. Not exactly sure though

Step-by-step explanation:

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Se van a transportar sacos que contienen 50 kg de azúcar cada uno, el camión que se va utilizar para el transporte de los sacos

LekaFEV [45]

Function: $50x=8000$ (maximum number of packages: 160)

Step-by-step explanation:

In this problem, we have:

$C=8 ton = 8000 kg$ is the capacity of the truck (the amount of mass that can be stored in the truck)

p = 50 kg is the mass of each package that need to be stored in the truck

We can find the number of packages that can be transported as follows: calling this number x, the total mass of x packages is

$p\cdot x$

This amount should be at most equal to the capacity of the truck, therefore:

$px=c$

And substituting the numbers,

$50x=8000$

And solving the equation, we can found the number of packages that can fit into the truck:

$x=\frac{8000}{50}=160$

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7 0

2 years ago

6(x + 3) − 3 = 39 whats the solution of x?

Naily [24]

Answer:

x = 4

Step-by-step explanation:

6(x+3)-3= 39

6x+18-3 =39

6x+15 =39

-15 -15

6x= 24

/6 /6

x=4

4 0

2 years ago

Read 2 more answers

coppers mother gives him $79 to the store, he buys 15 loaves of bread and 28 cartons of juice each bread is $3 and each juice ca

Leviafan [203]

He doesn't have a positive number. Add $45 and $112 together and it exceeds $79

3 0

2 years ago

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A serving of a certain cereal has 8 grams of sugar in 1 portion. Which equation shows how the amount of sugar and the number of

STatiana [176]

8s = 1p.

Hope this helps!

5 0

3 years ago

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Which expression correctly simplifies (312415)56?

Andreyy89

Answer:

$\sf C)\quad \large\text{$\dfrac{3^{\frac{5}{12}}}{4^{\frac{1}{6}}}$}$

Step-by-step explanation:

Given expression:

$\large\text{$\left(\dfrac{3^{\frac{1}{2}}}{4^{\frac{1}{5}}}\right)^\frac{5}{6}$}$

$\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:$

$\large\text{$\implies \dfrac{\left(3^{\frac{1}{2}}\right)^\frac{5}{6}}{\left(4^{\frac{1}{5}}\right)^\frac{5}{6}}$}$

$\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:$

$\large\text{$\implies \dfrac{3^{(\frac{1}{2}\times \frac{5}{6})}}{4^{(\frac{1}{5}\times \frac{5}{6})}}$}$

Simplify:

$\large\text{$\implies \dfrac{3^{\frac{5}{12}}}{4^{\frac{1}{6}}}$}$

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1 year ago