A rectangle with sides 15 and w has perimeter

We want this quantity to be at most 50, so it must be less than or equal to 50:

For the record, this implies that

So, the width can be at most 10.
Answer:
6 buses
Step-by-step explanation:
138 students / 23 students per bus = 6 buses
I think 20×5=100 then 100÷2
Answer:
(m−5)(2m−2)
=(m+−5)(2m+−2)
=(m)(2m)+(m)(−2)+(−5)(2m)+(−5)(−2)
=2m2−2m−10m+10
=2m2−12m+10
A. Annual Savings = $60 * 12 = $720
b. $8384.48