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2 years ago

What is the z-score of a newborn who weighs 4,000 g?.

Mathematics

1 answer:

ExtremeBDS [4]2 years ago

4 0

What is the z-score of a newborn who weighs 4000 g?
For this question the answer is
-1

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Write explicit formula for a1=3, r=-2; then generate 1st 5 terms

Crazy boy [7]

Answer:

an = 3(-2)^(n-1)
3, -6, 12, -24, 48

Step-by-step explanation:

These variable names, a1, r, are commonly used in relationship to geometric sequences. We assume you want the terms of a geometric sequence with these characteristics.

a1 is the first term. r is the ratio between terms, so is the factor to find the next term from the previous one.

a1 = 3 (given)

a2 = a1×r = 3×(-2) = -6

a3 = a2×r = (-6)(-2) = 12

a4 = a3×r = (12)(-2) = -24

a5 = a4×r = (-24)(-2) = 48

The first 5 terms are 3, -6, 12, -24, 48.

The explicit formula for the terms of a geometric sequence is ...

an = a1×r^(n -1)

Using the given values of a1 and r, the explicit formula for this sequence is ...

an = 3(-2)^(n -1)

6 0

3 years ago

Can someone help me with question 9

Troyanec [42]

Please refer the pictures below-

Hence the area of the road is 9600m2

8 0

3 years ago

In order to make 6 dozen cookies, you must use 3 eggs in the batter. How many eggs would be required to make 48 dozen cookies? U

Brrunno [24]

Step-by-step explanation:

Well 6 times 8 is 48 so

8 times 3 is 24

7 0

3 years ago

Read 2 more answers

party trays, which cost $14.00 to make not including labor, are sold for $35.00. if two people work 8 hour shifts making the tra

olasank [31]

Answer:

I think its $76

Step-by-step explanation:

please help brainly.com/question/20406553

7 0

2 years ago

Rewrite the expression in terms of the given function 1/1-sinx - sinx/1+sinx

Feliz [49]

Your question seems a bit incomplete, but for starters you can write

$\dfrac1{1-\sin x}-\dfrac{\sin x}{1+\sin x}=\dfrac{1+\sin x}{(1-\sin x)(1+\sin x)}-\dfrac{\sin x(1-\sin x)}{(1+\sin x)(1-\sin x)}=\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}$

Expanding where necessary, recalling that $(1-\sin x)(1+\sin x)=1-\sin^2x=\cos^2x$ , you have

$\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}=\dfrac{1+\sin x-\sin x+\sin^2x}{\cos^2x}=\dfrac{1+\sin^2x}{\cos^2x}$

and you can stop there, or continue to rewrite in terms of the reciprocal functions,

$\dfrac{1+\sin^2x}{\cos^2x}=\sec^2x+\tan^2x$

Now, since $1+\tan^2x=\sec^2x$ , the final form could also take

$\sec^2x+\tan^2x=\sec^2x+(\sec^2x-1)=2\sec^2x-1$

or

$\sec^2x+\tan^2x=(1+\tan^2x)+\tan^2x=1+2\tan^2x$

7 0

3 years ago