The average rate of change (AROC) of a function f(x) on an interval [a, b] is equal to the slope of the secant line to the graph of f(x) that passes through (a, f(a)) and (b, f(b)), a.k.a. the difference quotient given by
![f_{\mathrm{AROC}[a,b]} = \dfrac{f(b)-f(a)}{b-a}](https://tex.z-dn.net/?f=f_%7B%5Cmathrm%7BAROC%7D%5Ba%2Cb%5D%7D%20%3D%20%5Cdfrac%7Bf%28b%29-f%28a%29%7D%7Bb-a%7D)
So for f(x) = x² on [1, 5], the AROC of f is
![f_{\mathrm{AROC}[1,5]} = \dfrac{5^2-1^2}{5-1} = \dfrac{24}4 = \boxed{6}](https://tex.z-dn.net/?f=f_%7B%5Cmathrm%7BAROC%7D%5B1%2C5%5D%7D%20%3D%20%5Cdfrac%7B5%5E2-1%5E2%7D%7B5-1%7D%20%3D%20%5Cdfrac%7B24%7D4%20%3D%20%5Cboxed%7B6%7D)
Step-by-step explanation:
As ANC are collinear,
AB+BC=AC
so,
18+BC = 41
BC = 41-18
BC = 23 is the answer.
Answer:
Cos;
26 degrees
Step-by-step explanation:
Recall: SOH CAH TOA
Reference angle = y°
Adjacent side = 18 in.
Hypotenuse = 20 in.
We would apply the trigonometric function CAH since we are dealing with the Adjacent side (A) and the Hypotenuse (H). Thus:
Cos y° = Adj/Hyp
Cos y° = 18/20
Cos y° = 0.9
y° = cos^{-1}(0.9)
y = 25.8419328° ≈ 26 degrees (nearest whole degree)
The answers are:
Cos and 26 degrees
Answer:
4
Step-by-step explanation:
pythagoras theorem = a* + b* = c* ( by '*' i mean squared)
2* + b* = square root twenty
4 + b* = 20
b* = 16
b = 4
Answer:
x=4/3 or x=-7/2
Step-by-step explanation:
(3x-4)(2x+7)
