Answer:
11x-55-5a+ax
11(x-5)+a(x-5)
(11+a)(x-5)
Step-by-step explanation:
First you factor out the common factors
for(11x-55) is would be 11 as both of these figures are the multiple of 11
for(ax-5a) the common factor is a which will be factor out
Then after doing the process you will get
11(x-5)+a(x-5)
then factor out(x-5)which will give you
(11+a)(x-5)
Answer:
The answer is given below
Step-by-step explanation:
The addition postulate for line segment states that if we have points A, C and a point B on line AC, The distance between points A and C can be given as:
AC = AB + BC
Point A is at -6, point B is at -1, point C is at +2 and point D is at point 8.
Therefore using line segment postulates:
AD = AB + BC + CD
But AB = -1 - (-6)= -1 + 6 = 5
BC = 2- (-1) = 2 +1 = 3
CD = 8 - (+2) = 8 - 2 = 6
Also AD = 8 - (-6) = 8 + 6 = 14
To prove AD = AB + BC + CD
AD = 5 + 3 + 6 = 14
n = the number
2(n + 3) is the expression
Answer: No it's not possible to form a triangle
Why not? Because the shorter sides 2 ft and 3 ft don't add to a result longer than 7 ft
2+3 = 5
For a triangle to be possible, the sum of any two sides must be larger than the third side. Refer to the triangle inequality theorem.
Answer:
Point slope form
y - 9 = 4(x-1)
Equation of the straight line passing through the point (1,9) and slope 'm' = 4 is 4 x - y +5=0
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the points are (1,9) and (-1,1)
slope of the line
m = 
m = 4
<u><em>step(ii):-</em></u>
Equation of the straight line passing through the point (1,9) and slope 'm' = 4
y-y₁ = m( x-x₁)
y - 9 = 4(x-1)
y -9 = 4x-4
4 x - y -4+9 =0
4 x - y +5=0
Equation of the straight line passing through the point (1,9) and slope 'm' = 4 is 4 x - y +5=0
