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irga5000 [103]
3 years ago
12

Plz help me I begg plzzzzz

Mathematics
2 answers:
Keith_Richards [23]3 years ago
8 0

Answer:

-3.42857142857

You get this when you use the order of operations, so you do parentheses first, then exponents, then addition or subtraction, and after that you do multiplication and division.

Damm [24]3 years ago
6 0

I hope this helps you

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I need some help on this question. I sent a screenshot on this.
morpeh [17]

Answer: 1/2

Step-by-step explanation:

I'm assuming this is rise over run. The rise is 1 and the run is 2.

Remember, \frac{rise}{run}

4 0
1 year ago
After chamar poured 2 liters of water into a large jug, the jug contained 10 liters of water. How many liters were in the jug to
tatyana61 [14]

Answer:

8

Step-by-step explanation:

10 - 2 = 8

7 0
3 years ago
Read 2 more answers
Please help! I don’t really have a grasp on word problems and they tend to stress me out a lot.
Ulleksa [173]

Answer:

Imani: 13r + 3d = 63

Abhasra: 12r + 12d = 132

Step-by-step explanation:

You just fill in the answers from the word problem. It has the answers.

8 0
3 years ago
What is this!!!!!! what is this
Temka [501]

Answer:

qn

Step-by-step explanation:

4 0
3 years ago
Cindy and Pam, working together, can clean the house in 10 hours. Working alone, Pam takes five times as long as Cindy. How long
Alborosie

c = Hours it take Cindy by herself

p =Hours it take Pam by herself

now, we know if they work together, they can finish in 10 hours, so let's take a peek at their rate.

whilst working together

in 1 hr Cindy has done 1/c "th" of the whole work

in 1 hr Pam has done 1/p "th" of the whole work

and since we know the whole work's time is 10 hours, in 1 hour they both have done 1/10 of whole lot, so

\stackrel{\textit{Cindy's rate}}{\cfrac{1}{c}}+\stackrel{\textit{Pam's rate}}{\cfrac{1}{p}}=\stackrel{\textit{fraction of total work}}{\cfrac{1}{10}}~\hfill \stackrel{\textit{since Pam takes 5 times longer}}{p=5c} \\\\\\ \cfrac{1}{c}+\cfrac{1}{5c}=\cfrac{1}{10}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{10c}}{10c\left( \cfrac{1}{c}+\cfrac{1}{5c} \right)=10c\left( \cfrac{1}{10} \right)}\implies 10+2=c\implies \stackrel{hours}{12=c}

5 0
3 years ago
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