His measurements could be as much as 0.1 cm wrong.
He measures 3 cm by 4 cm .
-- The smallest the area could possibly be is if both of his measurements were too big. The rectangle would actually be 2.9cm by 3.9cm, and the area would actually be (2.9 x 3.9) = 11.31 square-cm.
-- The biggest the area could possibly be is if both of his measurements were too small. The rectangle would actually be 3.1 cm by 4.1 cm, and the area would actually be (3.1 x 4.1) = 12.71 square-cm.
So the true area must be between 11.31 ≤ Area ≤ 12.71 .
Given that figure A with radius of 2 inches is dilated to form figure B, the radius of B will be given by: Radius B=(radius A)×(scale factor) but scale factor=4 thus Radius of B will be: 2×4 =8 inches