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Stolb23 [73]
3 years ago
6

What is the equation of the blue line

Mathematics
2 answers:
makvit [3.9K]3 years ago
5 0

Answer:

y=2x+3

Step-by-step explanation:

tekilochka [14]3 years ago
4 0
F(c)= 2x+3 this should be the answer
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Solve using Quadratic Formula <br>x^2 + 3x - 3 = 0​
katrin [286]

Answer:

a= 1 , b= 3 , c= –3

x =  \frac{ - b \frac{ + }{}  \sqrt{ {b}^{2}  - 4ac} }{2a}  \\ x =  \frac{ - 3  \frac{ + }{} {}  \sqrt{ {3}^{2}  - 4(1)( - 3)} }{2(1)}  \\  =   \frac{ - 3 \frac{ + }{}  \sqrt{9 + 12} }{2}  =  \frac{ - 3 \frac{ + }{} \sqrt{21}  }{2}  \\ \\  x =  \frac{ - 3 \frac{ + }{} \sqrt{21}  }{2}  \\  \\ x = 0.79 \\ x =  - 3.79

I hope I helped you^_^

4 0
3 years ago
Could someone please help me out with this?​
natka813 [3]
5•3=25 :) hope this helps!
7 0
3 years ago
Read 2 more answers
-5(-× -6) =31<br> Solve the equation
faust18 [17]

Answer: I believe the answer to this question is: X= 1/5.

6 0
4 years ago
A vehicle with a mass of 500 kg rolls down a slanted road with an acceleration of 0.04 m / s2. The frictional force
lilavasa [31]

Answer:

a) Sketch  in annex

b)  angle is  22 °

c) grade of the hill is  tan 22°  =  0,40

Step-by-step explanation: See Annex for free body diagram

According to Newton´s second law

∑ Fy  =  0      ⇒   mg cos ∠CAB - Fn  = 0

Notice  ∠ CAB  =  ∠ POD  ( They have perpendicular sides )

mg  =  500 Kg * 9.8 m/sec²     ⇒   mg  =   4900 [N]

mg cos ∠CAB - Fn  = 0      ⇒  4900*cos ∠CAB   =  Fn      (1)

∑ Fx  =  ma

mg* sin  ∠CAB  - Fr  =  500* 0.04 m/sec²   =  20 [N]

4900 * sin  ∠CAB   =  1800  + 20  [N]

sin  ∠CAB  = 1820 / 4900   ⇒  sin  ∠CAB  = 0.3714

From tables we get

∠CAB  = 22°

6 0
4 years ago
How can you translate words into equations?
Lyrx [107]

Answer:

try to look out for words such as more than, less than, twice as much, half as much, in addition to, took away something, etc

Step-by-step explanation:

hope this helped!

3 0
3 years ago
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