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Tpy6a [65]
3 years ago
5

A 77-year-old female is unresponsive, but breathing and with a pulse. on scene, a family member hands you an official document s

tating that the patient does not want feeding tubes, ventilators, or other long-term life support equipment to keep her alive. there is no mention of whether to administer life-saving drugs or withhold cardiopulmonary resuscitation. the emt would recognize this document as a(n):
Biology
1 answer:
malfutka [58]3 years ago
7 0
This would be called a "living will".
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List the three domains, characteristics of each, and
bixtya [17]

Answer:

the three domains are Eukarya Archae and Eubacteria

Explanation:

an example of Eukarya is plants and animals

an example of Archae is methanogens

an example of bacteria is bacteria such as e.coli

6 0
3 years ago
Part 1: crossing beak color and tail-feather length cross a yyll (heterozygous parent with dominant traits) with yyll (homozygou
Luba_88 [7]
Since you forgot to put capital letters i assume it's like this:

1)A <span>Cross between YyLl (heterozygous parent with dominant traits) and yyll (homozygous parent with recessive traits).

</span><span> 2)offspring YyLl: 400, Yyll: 100, yyLl: 100 and yyll: 400

</span>The recombinant offspring are allele combinations that are not directly inherited from the parents.
The parents combinations:<span>YyLl and yyll,
</span>The recombinant combinations: Yyll and yyLl
The other types are exacly like the parents so they are not recombinant.

answer: Yyll and yyLl


3 0
3 years ago
Gregor Mendel crossed true-breeding plants with green pea pods with true-breeding plants with yellow pea pods. The resulting F1
Alchen [17]

Answer:

A. Mendel observed green and yellow pea pods in a 3:1 ratio because the F1 generation was heterozygous.

Explanation:

The two true breeding plants in the parental population were homozygous (that is what true breeding means). Therefore, their cross would lead to all heterozygous offspring (see attached punnet square). Green is the dominant characteristic, so all F1 plants had a green phenotype, but Gg genotype.

The F1 cross would therefore be Gg x Gg. See attached punnet square.

The genotypes in the F2 generation are 1 GG: 2 Gg: 1 gg 1

Therefore, the phenotypic ratio is 3 green pea pods (Gg or GG): 1 yellow (gg)

Download pdf
4 0
3 years ago
In a small cramped kitchen, you and some friends are preparing a spaghetti dinner. the water is boiling and the pasta is now rea
DerKrebs [107]

In a small cramped kitchen, you and some friends are preparing a spaghetti dinner. the water is boiling and the pasta is now ready to be carried to the sink to drain. you pick up the pot of bubbling pasta water and start in the direction of the sink. the pot holder slips slightly, causing the water to splash onto your arm. the scalding water burns your forearm. you are experiencing a lot of pain, with a red, blistering burn on your arm.

The appropriate first response will be to cool the affected arm under running water and application of ice pack. The cold temperatures will lower the pain that is being felt.

6 0
3 years ago
How do small intestinal epithelial and root hair cells function in nutrient procurement?
Usimov [2.4K]
<span>Villi are hair-like structures covered with epithelial cells measuring 1.5 mm that line the mucous inner membrane of the small intestine. The epithelial cells of the villi contain microvilli and are responsible for the absorption of nutrients. Being so small and numerous, they effectively increase the absorptive surface area of the small intestine. When the surface area increases, this is the time they absorb the nutrients. As for plants' root hair cells, they receive nutrients through osmosis. Root hair cells are adapted for this by having a large surface area to speed up osmosis. The absorbed water and minerals are transported through the roots to the rest of the plant where it is used for different purposes: It is a reactant used in photosynthesis. As we can see, both of them utilize increasing their surface area.</span>
8 0
3 years ago
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