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3 years ago

Rectangle ABCD has a perimeter represented by the expression 9x + 3. Rectangle PQRS has a

Mathematics

1 answer:

9966 [12]3 years ago

8 0

Answer:

D. $3x + 1$

Step-by-step explanation:

Perimeter of Rectangle ABCD = $9x + 3$

Perimeter of Rectangle PQRS = $6x + 2$

Difference between perimeter of Rectangle ABCD and Perimeter of Rectangle PQRS:

$(9x + 3) - (6x + 2)$

Open Parentheses

$9x + 3 - 6x - 2$

Collect like terms

$9x - 6x + 3 - 2$

$3x + 1$

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Murljashka [212]

-5/3-9/2x=3/2
-10/6-9/2x=9/6
-9/2x=19/6
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4 years ago

What is 3 3/4 x (-2/5) ?

Andrej [43]

Answer:

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Step-by-step explanation:

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3 years ago

Find the number b, where b>0, such that the average value of f(x)=3−27x2 on the interval [0,b] is equal to 2.

Ymorist [56]

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4 years ago

Vince has a rectangular rug in his room with an area of 10 ft the length of the rug is 18 inches longer than the width what coul

aev [14]

The length of the rug is 4 ft.

The width of the rug is 2.5 ft.

Explanation:

The area of the rug is 10 ft.

The length of the rug be l.

Let us convert the inches to feet.

Thus, $18 inches = 1.5 ft$

Thus, the length of the rug is $l=1.5+w$

Let the width of the rug be w.

Substituting these values in the formula of area of the rectangle, we get,

$A=length\times width$

$10=(1.5+w)(w)\\10=1.5w+w^2\\w^2+1.5w-10=0$

Solving the expression using the quadratic formula,

$w=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Substituting the values, we have,

$$w=\frac{-15 \pm \sqrt{15^{2}-4 \cdot 10(-100)}}{2 \cdot 10}\\$

$w=\frac{-15 \pm \sqrt{4225}}{20}$

$w=\frac{-15 \pm 65}{2 0}$

Thus,

$w=\frac{-15 + 65}{2 0}\\w=\frac{50}{20} \\w=2.5$ and $w=\frac{-15 - 65}{2 0}\\w=\frac{-80}{20} \\w=-4$

Since, the value of w cannot be negative, the value of w is 2.5ft

Thus, the width of the rug is 2.5ft

Substituting $w=2.5$ in $l=1.5+w$ , we get,

$l=1.5+2.5\\l=4$

Thus, the length of the rug is 4 ft.

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3 years ago

(1.5 x 10^4) + (2.97 x 10^6)

Fittoniya [83]

Answer:

Step-by-step explanation:

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3 years ago