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Alex Ar [27]
3 years ago
6

What is the sqaure root of 45n^5? In Radical Form.

Mathematics
2 answers:
laila [671]3 years ago
7 0
<span>45n^(5/2) is the answer

</span>
Vladimir [108]3 years ago
7 0
45 has to be broken into a perfect part and a non perfect part do 9 * 5 = 45 and then the variables also need to be separated n^5 would be n^4 * n
the sqrt of 9 = 3 and the sqrt of n^4 = n^2
3n^2 sqrt5n would be the final answer
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creativ13 [48]
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8 0
3 years ago
Twice the quantity b plus 9
mojhsa [17]

Answer:

2b+9

Step-by-step explanation:

Twice the quantity b is 2*b = 2b

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5 0
3 years ago
Help me please by solving and showing the steps:)
Lorico [155]

Answer:

-\frac{3\sqrt[3]{t} }{2}

Step-by-step explanation:

1: Write g(t) as y, resulting in y=-\frac{8}{27}t^3

2: Interchange the variables y and t, resulting in t=-\frac{8}{27}y^3

3: Multiply both sides by 27, resulting in 27t=-8y^3

4: Divide both sides by -8, resulting in -\frac{27t}{8}=y^3

5: Find the cube root of both sides, resulting in \sqrt[3]{-\frac{27t}{8} }=y

6: Apply a radical rule, resulting in -\sqrt[3]{\frac{27t}{8} } =y

7: Apply another radical rule, resulting in -\frac{\sqrt[3]{27t} }{\sqrt[3]{8} } =y

8: Simplify the denominator, resulting in  -\frac{\sqrt[3]{27t} }{2} =y

9: Apply yet another radical rule, resulting in -\frac{\sqrt[3]{27}\sqrt[3]{t}   }{2} =y

10: Simplify \sqrt[3]{27}, resulting in -\frac{3\sqrt[3]{t}   }{2} =y

3 0
3 years ago
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ExtremeBDS [4]

Answer;

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Hope this helps!

6 0
3 years ago
12.54 + (-24.673)<br><br><br> What’s the answer if you compute?
Zinaida [17]

Answer:

-12.133 would be your answer

8 0
3 years ago
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