The distance covered by the boat is 
Further explanation:
The Pythagorean formula can be expressed as,

Here, H represents the hypotenuse, P represents the perpendicular and B represents the base.
The formula for tan of angle a can be expressed as

Explanation:
The perpendicular AB. The length of AB is 
The angle of depression is 
One degree has 60 minutes.


The angle ADB is 

In triangle ABC.

In triangle ABD.

The distance boat can travel can be obtained as follows,

The distance covered by the boat is 
Kindly refer to the image attached.
Learn more:
1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
2. Learn more about equation of circle brainly.com/question/1506955.
3. Learn more about range and domain of the function brainly.com/question/3412497
Answer details:
Grade: High School
Subject: Mathematics
Chapter: Trigonometry
Keywords: perpendicular, person watching boat, top, lighthouse, angle of depression, angle of elevation, 200 feet tall, travel, sides, right angle triangle, triangle, altitudes, hypotenuse, on the triangle, hypotenuse, trigonometric functions.