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miv72 [106K]
3 years ago
13

If a ball is dropped from 160 cm and rebounds to 120 cm on the first bounce, how high will the ball be on the 2nd bounce

Mathematics
1 answer:
notka56 [123]3 years ago
6 0
The answer is 80 cetemeters
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3 years ago
Let f(x)=(5)x+12. Evaluate f(0) without using a calculator.
Lelu [443]

Answer:

f(0) = 12

Step-by-step explanation:

You want to substitute 0 for x

f(0) = 5(0) + 12

f(0) = 12

8 0
3 years ago
What is the center of the ellipse x2+5y2–45=0?
jeka94

Answer:

Center is at (0,0)

Step-by-step explanation:

An equation of ellipse in standard form is:

\displaystyle{\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2} = 1

Where center is at point (h,k)

From the equation of \displaystyle{x^2+5y^2-45=0}. First, we add 45 both sides:

\displaystyle{x^2+5y^2-45+45=0+45}\\\\\displaystyle{x^2+5y^2=45}

Convert into the standard form with RHS (Right-Hand Side) equal to 1 by dividing both sides by 45:

\displaystyle{\dfrac{x^2}{45}+\dfrac{5y^2}{45}=\dfrac{45}{45}}\\\\\displaystyle{\dfrac{x^2}{45}+\dfrac{y^2}{9}=1}

Therefore, the center of ellipse is at (0,0) since there are no values of h and k.

8 0
2 years ago
For which value of theta is sine theta = negative 1?
Ivan

Answer:

1) 270 degrees

2)  pi/4 rad

Step-by-step explanation:

1.) For which value of theta is sine theta = negative 1?

Given

sintheta = -1

theta = arcsin(-1)

theta = -90degrees

Since sin is negative in the third and 4th quadrant

In the third quadrant, theta = 180 + 90 = 270degrees

In the fourth quadrant, theta = 360 - 90 = 270 degrees

Hence the required value of theta is 270degrees

2) Given the radius of the circle to be 1, the y axis value will also be 1 units

Opposite = 1

adjacent = 1

hyp = √1²+1²

hyp = √2

sin theta = opp/hyp

sin theta = 1/√2

theta = arccsin(1/√2)

theta = 45 degrees

Express in radians

45 degrees = pi/4 radians

Hence the required angle in the first quadrant is pi/4 rad

4 0
3 years ago
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n200080 [17]

Answer:

$4.69

Step-by-step explanation:

HOPE THIS HELPEDDDD ❤✨

4 0
3 years ago
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