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3 years ago

PLEASE HELP ASAP 25 POINTS

Mathematics

1 answer:

Elena L [17]3 years ago

6 0

Answer: B

Step-by-step explanation:

2x - 3y = -7 → 2(2x - 3y = -7) → 4x - 6y = -14

-4x + 6y = -10 → 1(-4x + 6y = -10) → -4x + 6y = -10

0 = -24

FALSE

Since this makes a false statement, there are no solutions

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4 years ago

Giải phương trình y"= lnx

kipiarov [429]

Integrate both sides with respect to x :

$y''(x) = \ln(x) \implies \displaystyle \int y''(x)\,\mathrm dx = \int \ln(x)\,\mathrm dx$

On the right side, integrate by parts with

$f = \ln(x) \implies \mathrm df = \dfrac{\mathrm dx}x \\\\ \mathrm dg = \mathrm dx \implies g = x$

$\implies \displaystyle \int\ln(x)\,\mathrm dx = fg - \int g\,\mathrm df \\\\ \int\ln(x)\,\mathrm dx= x\ln(x) - \int \mathrm dx \\\\ \int\ln(x)\,\mathrm dx= x\ln(x) - x + C_1$

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$\displaystyle y'(x) = x\ln(x) - x + C_1$

Integrate both sides with respect to x by parts again, this time with

$f = \ln(x) \implies \mathrm df = \dfrac{\mathrm dx}x \\\\ \mathrm dg = x\,\mathrm dx \implies g = \dfrac{x^2}2$

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Then

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3 years ago

Yvonne put $4,000 in a savings account. at the end of 3 years, the account had earned $960 in simple interest. a. how much does

motikmotik

A) At the end of 3 years the amount in the account = Principal + Interest

Amount = 4000 + 960 = 4960

Amount at the end of 3 years = $4960

b) Formula for Rate , R = 100I/(PT)

Where I = Interest = 960, P = Principal = 4000, T= Time = 3 years

  R = (100 × 960) / ( 4000 × 3)

  R = 8

  Rate, R = 8% per annum.

c) If the rate was 1% more, R = 8 + 1 = 9% per annum

Interest, I = PRT/100

Interest, I =   4000 × 9 × 3 /100 = 1080

Amount in her account would have been = $4000 + $1080 = $5080

Amount more = $5080 - $4960 = $120

She would have had $120 more should the rate were 1% greater.

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3 years ago