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3 years ago

8

Rochelle is baking cookies and is using 2/3 cup white sugar and 1/4 cup brown sugar. What is the difference in the amounts of su

gar?

2 answers:

inysia [295]3 years ago

7 0

Answer:

its B guys

Step-by-step explanation:

mixer [17]3 years ago

3 0

Turn 1/4 into 3/12 and turn 2/3 into 8/12! the difference is 5/12 cup :)

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LA plane is trying to travel 250 miles at a bearing of 20° E of S, however, it ends 230 miles away from the

Semmy [17]

Answer:

The wind pushed the plane $65.01$ miles in the direction of $45.56 ^{\circ}$ East of North with respect to the destination point.

Step-by-step explanation:

Let origin, O, br the starting point and point D be the destination at 250 miles at a bearing of 20° E of S, but due to wind let D' be the actual position of the plane at 230 miles away from the starting point in the direction of 35° E of South as shown in the figure.

So, we have |OD|=250 miles and |OD'|=230 miles.

Vector $\overrightarrow{DD'}$ is the displacement vector of the plane pushed by the wind.

From figure, the magnitude of the required displacement vector is

$|DD'|=\sqrt{|AB|^2+|PQ|^2}\;\cdots(i)$

and the direction is $\alpha$ east of north as shown in the figure,

$\tan \alpha=\frac{|PQ|}{|AB|}\;\cdots(ii)$

From the figure,

$|AB|=|OA-OB|$

$\Rightarrow |AB|=|OD\cos 20 ^{\circ}-OD'\cos 35 ^{\circ}|$

$\Rightarrow |AB|=|250\cos 20 ^{\circ}-230\cos 35 ^{\circ}|$

$\Rightarrow |AB|=45.52$ miles

Again, $|PQ|=|OP-OQ|$

$\Rightarrow |PQ|=|OD\sin 20 ^{\circ}-OD'\sin 35 ^{\circ}|$

$\Rightarrow |PQ|=|250\sin 20 ^{\circ}-230\sin 35 ^{\circ}|$

$\Rightarrow |PQ|=46.42$ miles

Now, from equations (i) and (ii), we have

$|DD'|=\sqrt{|45.52|^2+|46.42|^2}=65.01$ miles, and

$\tan \alpha=\frac{|46.42|}{|45.52|}$

$\alpha=\tan^{-1}\left(\frac{|46.42|}{|45.52|}\right)=45.56 ^{\circ}$

Hence, the wind pushed the plane $65.01$ miles in the direction of $45.56 ^{\circ}$ E astof North with respect to the destination point.

5 0

3 years ago

-7z - 7 ≤ -5z + 5 need help sloving

V125BC [204]

-7z - 7 ≤ -5z + 5

- 7 - 5 ≤ -5z + 7z
-12 ≤ 2z
-12/2 ≤ z
-6 ≤ z or z>= -6

7 0

3 years ago

Read 2 more answers

Two trains leave towns 471 miles apart at the same time and travel toward each other. One train travels 21 miles per hour slower

nadya68 [22]

Let the slower train's velocity be x-21

Let the faster train's velocity be x

We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.

The approach rate is given by Distance/time = 471/3 = 157mpH

x+x-21=157

2x=157+21

2x=178

x=89mph

The slower train is travelling 89-21 = 68mph

The faster train is travelling 89mph.

7 0

1 year ago

HELP IM ON THE LAST ONE ILL GIVE BRAINLIEST

xxMikexx [17]

Answer:

this is hard what grade is this for

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Please answer thank u ASAP.

Neko [114]

Answer:

a?

Step-by-step explanation:

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3 years ago