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oksano4ka [1.4K]
3 years ago
11

A high-production operation was studied during an 80-hr period. During that time, a total of seven equipment breakdowns occurred

for a total lost production time of 3.8 hr, and the operation produced 38 defective products. No setup was performed during the period. The operation cycle consists of a processing time of 2.14 min, a part handling time of 0.65 min, and a tool change is required every 25 parts, which takes 1.50 min. Determine the scrap rate q in % during the period."
Business
1 answer:
Shkiper50 [21]3 years ago
4 0

Answer:

scrape rate  = \frac{38}{1566} = 2.43 \%

Explanation:

Given data;

studying period of production  = 80 hr

lost time of production = 3.8 hr

defective product = 38

Processing time = 2.14 min

handling time  =  0.65 min

total part = 25 part

cycle time pf unit operation

T_C = Process\ time + handling\ time + \frac{change\ time\ for\ each part}{total part}

T_c = 2.14 + 0.65 + \frac{1.50}{25} = 2.85 min

total production hour is calculated as

production hour  = 80 - 3.8 = 76.2 hr

NUmber of part produce= \frac{ 76.2 \times 60}{2.85}= 1604 parts

acceeptable parts are = 1604 - 38 = 1566 parts

scrape rate q = \frac{defective\ product}{acceptable\ product}

scrape rate  = \frac{38}{1566} = 2.43 \%

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Answer:

Part a: The probability of breaking even in 6 tosses is 0.3125.

Part b: The probability that one payer wins all the money after the 10th toss is 0.0264.

Explanation:

Part a

P(success)=1/2=0.5

P(Failure)=1/2=0.5

Now for the break-even at the sixth toss

P(Break Even)=P(3 success out of 6)

P(3 success out of 6)

=^6C_3/(2^6)\\=5/16\\=0.3125

So the probability of breaking even in 6 tosses is 0.3125.

Part b:

So the probability that one of the player wins all the money after the 10th toss is given as the tenth toss is given as a win so

Wins in 9 tosses is given as 9!/7!=72

The probability that the other person wins

Wins in 8 out of 10 tosses is given as 10!/8!(10-8)!=10!/8!2!=45

So the probability of all the money is won by one of the gambler after the 10th toss is given as

P=number of wins in 9 tosses-Number of wins in 10 tosses/total number of tosses

P=(72-45)/2^16

P=0.0264

So the probability that one payer wins all the money after the 10th toss is 0.0264.

8 0
3 years ago
If current rates of use and extraction do not change, known natural gas reserves are expected to last ____________ years.
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40-55 years is the expected number of years that known natural gas reserves are expected to last given that the current rates of use and extraction<span> do not change. The world has 40-55 years left to find an alternative to oil before it runs out.</span> 

 

 

 

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7 0
3 years ago
Mention ONE other source of wealth other than inheritance
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Answer:

Power is another source other than inheritance.

Hope this helped you!

Explanation:

6 0
3 years ago
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Minimum-wage laws can keep wagesa.a) above equilibrium and cause a surplus of labor.b) above equilibrium and cause a shortage of
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Answer:

The correct answer is option a.

Explanation:

Minimum wages can be defined as the minimum level of wages that an employer is supposed to pay to workers for their work. It cannot be reduced through an individual contract or collective agreement.  

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4 0
3 years ago
An initial time study was done on a process with the following results​ (in minutes). Based on the data obtained so​ far, assumi
kiruha [24]

Answer: 24.60 minutes (2dp)

Explanation:

The question is essentially asking that we find the Standard Time it takes to serve a customer.

To do this we would have to calculate the averages of the different elements and then use this to find the normal time which we can then use to find the Standard Time.

Element 1

= (3 + 4 + 4 + 3 + 3)/5

= 3.4

Element 2

= ( 9 + 8 + 10 + 11 + 10)/5

= 9.6

Element 3

= ( 7 + 8 + 6 + 7 + 8)/5

= 7.2

We then calculate the normal times by multiplying each of the individual means with their performance ratings.

That would be,

Element A

= 3.4 * 70%

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= 10.56

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= 8.64

We then add up the normal times to get the total normal time

= 2.38 + 10.56 + 8.64

= 21.58 minutes

Now we can solve for the standard time using this formula,

Standard time = Normal time (1+Allowance factor)

= 21.58 ( 1 + 0.14)

= 24.6012 minutes

= 24.60 minutes (2dp)

The time per unit customer served is 24.60 minutes.

If you need any clarification please do comment. Cheers.

6 0
3 years ago
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