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4 years ago

Lines a and b are perpendicular. The equation of line a is y=13x+3. What is the equation of line b?

Mathematics

1 answer:

Harlamova29_29 [7]4 years ago

3 0

Any equation that includes y=1/13x.

m must be 1/13

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State three measures that could be the side lengths of a right triangle. Justify your answer.

Marizza181 [45]

Answer: I think its either A or C

Step-by-step explanation:

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3 years ago

Find the distance between the points (-1,-2) and (5,2). Simplified radical form.

frozen [14]

Answer:

2 $\sqrt{13}$

Step-by-step explanation:

Using the distance formula,

$\sqrt{( x_{2}-x_{1} )^2+(y_{2} -y_{1})^2 }$

We just need to plug in the numbers.

So $\sqrt{(-1-5)^2+(-2-2)^2}$

Then we simplify it to

$\sqrt{(-6)^2+(-4)^2} , to \sqrt{36+16}$

Finally, we get

$\sqrt{52}$ , which is $2\sqrt{13}$ when simplified.

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3 years ago

8. Use the information in the table to write 5 ordered pairs that have cats as the input value

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3 years ago

Write a polynomial in standard form that meets the following conditions. Assume a=1 and your function is f(x), The zeros are 5 a

jeka57 [31]

Polynomials are equations that uses variables and several terms

The polynomial in standard form is f(x) = x^2 - x -20

<h3>How to determine the polynomial</h3>

The polynomial has 2 zeros.

So, the form of the polynomial is:

f(x) = a(x - x1)(x - x2)

The zeros of the polynomial are 5 and -4.

So, the equation becomes

f(x) = a(x - 5)(x + 4)

The value of a = 1.

So, we have;

f(x) = 1(x - 5)(x + 4)

This gives

f(x) = (x - 5)(x + 4)

Expand

f(x) = x^2 - x -20

Hence, the polynomial in standard form is f(x) = x^2 - x -20