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ser-zykov [4K]
2 years ago
15

Help with this math problem

Mathematics
1 answer:
lutik1710 [3]2 years ago
6 0

Answer:

-4z^{2} +5z^{2} -2x+4\frac{1}{2} zy^{2}

7 apples+7 oranges

2x^{2} y+5xy^{2}-3xy

Step-by-step explanation:

You might be interested in
X and y intercepts of -3x+4y=-36
Andrews [41]
X intercept is 12
Y intercept is 9.
To find answer just cover up the one you don't want.
For x it would be -3x=-36
For y it would be 4y=-36
8 0
3 years ago
Please help me with this and explain how u did it step by step
joja [24]

The domain of the third piece of the graph is contained in interval <u>B. (12, 20)</u>.

<h3>What is the domain of a graph?</h3>

The domain of a graph consists of all the input values shown on the x-axis.

The input values (domain) are shown on the x-axis, unlike the range, whose output values are shown on the y-axis.

Therefore, the domain comprises the independent variables or values, which can be determined using the function, y = f(x).

Thus, the domain of the third piece of the graph can be determined in interval <u>B. (12, 20)</u>.

Learn more about domain and range at brainly.com/question/10197594 and brainly.com/question/2264373

#SPJ1

6 0
1 year ago
H U R R Y 2 0 P O I N T S
koban [17]

Distance is 26 hehhehehehehe :)

4 0
3 years ago
An engineer is designing a large steel pad to be installed on the deck of an aircraft carrier. Its total volume will be 18 yd^3.
Shtirlitz [24]

Answer:

The cost of the material for the full-sized pad is;

d) 222,750.00

Step-by-step explanation:

The parameters of the steel pad and the scale model are;

The volume of the deck = 18 yd³

The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick

The weight of the sample, m₂ = 75 lbs

The cost of the steel, P = $55/lb

The dimensions of the sample in yards are;

6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0.\overline 1 yards

The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0.\overline 1 yd. =  (1/3) yd.³

The density of the sample material, ρ = m₂/V₂

∴ The density of the sample material, ρ = 75 lbs/((1/3)yd.³) = 225 lbs/yd³

Therefore, the density of the material of the pad, ρ = 225 lbs/yd³

The mass of the steel  pad, m₁ = ρ × V₁

∴ The mass of the steel  pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs

The cost of the material for the full-sized steel pad, C = m₁ × P

∴ C = 4,050 lbs × $55/lb = $222,750

6 0
3 years ago
|-5x-5|=45 what is the solutions
Paha777 [63]

Answer:-10

Step-by-step explanation:

45 +5=-5x

-5x=50

X=-10

7 0
3 years ago
Read 2 more answers
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