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solong [7]
2 years ago
8

X−2y=−1

Mathematics
1 answer:
nikitadnepr [17]2 years ago
6 0

b.

they're just intersecting.

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antiseptic1488 [7]
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12/18 = 8/x <=> 2/3 = 8/x <=> x = (3*8)/2 = 12;
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What is the quotient of 17 and x
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4

Step-by-step explanation:

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5a - 9 + a = 9
Ne4ueva [31]

Answer:

a = 3

Step-by-step explanation:

1) Simplify 5a - 9 + a to 6a - 9.

6a - 9 = 9

2) Add 9 to both sides.

6a = 9 + 9

3) Simplify 9 + 9 to 18.

6a = 18

4) Divide both sides by 6.

a =  \frac{18}{6}

5) Simplify 18/6 to 3.

a = 3

Therefor, the answer is, a = 3.

7 0
3 years ago
Which lists the steps in the correct order to find the median of this data set?
Fofino [41]

The median of the data set can be found as follows:

1. Put the numbers in order (from least to the greatest): 16, 18, 23, 24, 29, 30

2. Cross off high/low pairs: 16, 18, (23, 24,) 29, 30

3. Divide the sum by 2: (23 + 24)/2 = 23.5

<h3>What is the Median?</h3>

The median of a data set is the data value at the middle of the data set when it is ordered.

Steps to find the median of the data set, 24, 16, 23, 30, 18, 29:

1. Put the numbers in order (from least to the greatest)

16, 18, 23, 24, 29, 30

2. Cross off high/low pairs: 16, 18, (23, 24,) 29, 30

3. Divide the sum by 2: (23 + 24)/2 = 23.5

4

The median is therefore, 23.5.

Learn more about the median on:

brainly.com/question/26177250

3 0
2 years ago
The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
Mama L [17]

Answer:

a) P(Y > 76) = 0.0122

b) i) P(both of them will be more than 76 inches tall) = 0.00015

   ii) P(Y > 76) = 0.0007

Step-by-step explanation:

Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

To find - (a) If a man is chosen at random from the population, find

                    the probability that he will be more than 76 inches tall.

              (b) If two men are chosen at random from the population, find

                    the probability that

                    (i) both of them will be more than 76 inches tall;

                    (ii) their mean height will be more than 76 inches.

Proof -

a)

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{S.D}) > \frac{( 76- mean)}{S.D})

                 = P(Z >  \frac{( 76- mean)}{S.D})

                 = P(Z > \frac{76 - 69.7}{2.8})

                 = P(Z > 2.25)

                 = 1 - P(Z  ≤ 2.25)

                 = 0.0122

⇒P(Y > 76) = 0.0122

b)

(i)

P(both of them will be more than 76 inches tall) = (0.0122)²

                                                                           = 0.00015

⇒P(both of them will be more than 76 inches tall) = 0.00015

(ii)

Given that,

Mean = 69.7,

\frac{S.D}{\sqrt{N} } = 1.979899,

Now,

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{\frac{S.D}{\sqrt{N} } })) > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- 69.7)}{1.979899 }))

                 = P(Z > 3.182)

                 = 1 - P(Z ≤ 3.182)

                 = 0.0007

⇒P(Y > 76) = 0.0007

6 0
3 years ago
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