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3 years ago

Complete the statement using > or <.

2 answers:

5 0

If your teacher or whoever asks you how you did it:

"First, I made common denominators by turning -3/4 into -6/8. Then I plugged in into the problem. -6/8 is less than -5/8.

lisabon 2012 [21]3 years ago

4 0

-3/4 = -6/8

-6/8 < -5/8

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9x9x9x9x7x7 index notation

azamat

Answer:

321,489 is the answer I got

Step-by-step explanation:

(sorry if wrong/incorrect!)

6 0

4 years ago

Determine the type and number of solutions of x^2 + 10x − 25 = 0. A two real solutions B one real solution C two imaginary solut

klemol [59]

Answer:

two real solution

Step-by-step explanation:

x^2 + 10x − 25 = 0

we can solve this by finding out the value of x

lets assume the equation is a\times x^{2}+b\times x+c=0

x=-b\pm \sqrt{(b^{2}-4ac)}\div 2a

x=-10\pm\sqrt{100+4*25}\div2

x=-5\pm5\sqrt2

then we get both real value of x

so two real solution

4 0

4 years ago

Solve:<br> 22,440=6,200e^0.06T<br><br> 22,440=6,200e^0.1T

Tomtit [17]

Answer:

$22440=6200e^{0.06T}$

$\implies \dfrac{561}{155}=e^{0.06T}$

$\implies \ln\dfrac{561}{155}=\ln e^{0.06T}$

$\implies \ln\dfrac{561}{155}=0.06T$

$\implies T=\dfrac{50}{3}\ln\dfrac{561}{155}$

$\implies T=21.43826314...$

$22440=6200e^{0.1T}$

$\implies \dfrac{561}{155}=e^{0.1T}$

$\implies \ln\dfrac{561}{155}=\ln e^{0.1T}$

$\implies \ln\dfrac{561}{155}=0.1T$

$\implies T=10\ln\dfrac{561}{155}$

$\implies T=12.86295789...$

3 0

2 years ago

3. The Leakey Shipping Company uses small containers with a volume of 2.5 m3and large containers with a volume of 4 m3. A shipme

Serga [27]

Given:

• Volume of small containers = 2.5 m³

• Volume of large containers = 4 m³

• Number of containers in the shipment = 140

• Total volume = 440 m³

Let's find the number of the size of each container used.

Let s represent the number of small containers

Let L represent the number of large containers.

• Equation for number of containers:

s + L = 140

• Equation for total volume:

2.5s + 4L = 140

Hence, we have the set of equations:

s + L = 140...........................equation 1

2.5s + 4L = 440...................equation 2

Let's solve the set of equations simultaneously using substitution methos.

Rewrite equation 1 for L:

L = 140 - s...........................equation 3

Substitute (140 -s) for L in equation 2:

2.5s + 4(140 - s) = 440

Apply distributive property:

2.5s + 4(140) + 4(-s) = 440

2.5s + 560 - 4s = 440

Combine like terms:

2.5s - 4s + 560 = 440

-1.5s + 560 = 440

Subtract 560 from both sides:

-1.5s + 560 - 560 = 440 - 560

-1.5s = -120

Divide both sides by -1.5:

$\begin{gathered} \frac{-1.5s}{-1.5}=\frac{-120}{-1.5} \\ \\ s=80 \end{gathered}$

Substitute 80 for s in either of the equations.

Take equation 3.

L = 140 - s

L = 140 - 80

L = 60.

Therefore, we have the solutions:

s = 80 and L = 60

Therefore, the company used 80 small containers and 60 large containers

5 0

1 year ago

Is it proportional or non proportional??

tankabanditka [31]

Answer:

Was meinen Sie

Step-by-step explanation:

Hast du die dritte Klasse nicht bestanden? benutze dein Gehirn.

6 0

3 years ago