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Morgarella [4.7K]
3 years ago
13

Which graph represents a proportional​ relationship? Explain. Graph A Graph B Graph C x y graph x y graph

Mathematics
1 answer:
larisa [96]3 years ago
7 0

Answer:

C

Step-by-step explanation:

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Find the quotient 5 2/3 ÷ 3/5 leave answer as a mixed number in simplest form.​
Ainat [17]

Answer:

9\frac{4}{9}

Step-by-step explanation:

Exact from:

\frac{85}{9}

Decimal Form:

9.4

Mixed Number Form:

9\frac{4}{9}

Give me Brainllest

8 0
3 years ago
Circle A has a circumference of 8/3 m. Circle B has a diameter that is 3/2 times as long as Circle A’s diameter. What is the cir
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Answer:

the answer is 4

Step-by-step explanation:

if my calculations are right

6 0
4 years ago
The National Center for Education Statistics reported that 47% of college students work to pay for tuition and livingexpenses. A
8090 [49]

Answer:

a) The 95% confidence interval for the population proportion of college students who work to pay for tuition andliving expenses is (0.4239, 0.5161).

b) The 99% confidence interval for the population proportion of college students who work to pay for tuition and living expenses is (0.4094, 0.5306).

c)The margin of error increases as the confidence level increases.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 450, p = 0.47

a) Provide a 95% confidence interval for the population proportion of college students who work to pay for tuition andliving expenses.

95% confidence interval

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.47 - 1.96\sqrt{\frac{0.47*0.53}{450}} = 0.4239

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.47 + 1.96\sqrt{\frac{0.47*0.53}{450}}{119}} = 0.5161

The 95% confidence interval for the population proportion of college students who work to pay for tuition andliving expenses is (0.4239, 0.5161).

b. Provide a 99% confidence interval for the population proportion of college students who work to pay for tuition andliving expenses.

95% confidence interval

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.47 - 2.575\sqrt{\frac{0.47*0.53}{450}} = 0.4094

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.47 + 2.575\sqrt{\frac{0.47*0.53}{450}}{119}} = 0.5306

The 99% confidence interval for the population proportion of college students who work to pay for tuition and living expenses is (0.4094, 0.5306).

c What happens to the margin of error as the confidence is increased from 95% to 99%?

The margin of error is the subtraction of the upper end by the lower end of the interval, divided by 2. So

95% confidence interval

M = \frac{(0.5161 - 0.4239)}{2} = 0.0461

99% confidence interval

M = \frac{(0.5306 - 0.4094)}{2} = 0.0606

The margin of error increases as the confidence level increases.

8 0
3 years ago
I need help fast!!
topjm [15]

Answer:

A:77 divided by 4

Step-by-step explanation:

77 divided by 4 = 19.25 and 19.25=19 1/4

7 0
4 years ago
Ms Jenkins art class has 35 students in art class.7 of the 35 students are girls.What percentage of the class is made up of boys
lubasha [3.4K]
28 boys I think ‍♀️.
3 0
3 years ago
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