Use the difference of squares theorem to find the solution of the following equation:
1 answer:
You might be interested in
Answer:
The correct option is x=3 , y=2
Step-by-step explanation:
According to the HL theorem if the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle then the triangles are congruent.
By using this theorem we can set up the system of equations as follows:
x=y+1 ...(1)
2x+3= 3y + 3 ..(2)
Now we will plug the value y+1 of equation 1 in equation 2.
2x+3 = 3y+3
2(y+1)+3=3y+3
2y+2+3=3y+3
2y+5=3y+3
Now combine the like terms:
5-3=3y-2y
2=y
y=2
Now plug the value y=2 in equation 1.
x=y+1
x=2+1
x=3
Thus the values of(x.y) are{(2,3)}
Therefore the correct option is x=3 , y=2 .....
