Answer:
Step-by-step explanation:
![x^{2} \sqrt{x} \sqrt[n]{x} \frac{x}{y} x_{123} \beta \beta \alpha \neq \geq \\ \left \{ {{y=2} \atop {x=2}} \right.](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%5Csqrt%7Bx%7D%20%5Csqrt%5Bn%5D%7Bx%7D%20%5Cfrac%7Bx%7D%7By%7D%20x_%7B123%7D%20%5Cbeta%20%5Cbeta%20%5Calpha%20%5Cneq%20%5Cgeq%20%5C%5C%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.)
Answer:
x ≈ 31.0°
Step-by-step explanation:
Using the tangent ratio in the right triangle
tanx = 
= 
, then
x = 
( ) ≈ 31.0° ( to 1 dec. place )
Answer:
if its on a coordinate plane the formula would be:
√(2x-1x)²+(2y-1y)²
Step-by-step explanation:
so if the coordinates were
A= (-3,2)
B= (4,2)
C= (4,-1)
D= (-3,-1)
for A to B it would be
√(4 - (-3)² + (2-2)²
√(7)² + (0)²
√(7·7) + (0·0)
√49+0
√49
or
7
I hope the explanation helped
Answer:
(-1, 6)
Step-by-step explanation:
The midpoint is the halfway point. So, if M is the midpoint of PQ, then simply take the distance between your P and M co-ordinates and apply that one more time to get to Q.
Your x value at point M is 5, and your x value at point P is 11.
11 and 5 are 6 units apart.
Since M is in the middle of P and Q, M is therefore 6 units apart from both P and Q on the x-axis, so we can subtract 6 from 5 to find Q's x co-ordinate of -1.
Your y value at point M is -2, and your y value at point P is -10.
-10 and -2 are 8 units apart.
Add 8 to M to find your y co-ordinate at point Q of 6.
Your Q point is at (-1, 6).
