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a_sh-v [17]
3 years ago
15

A quadrilateral has angles that measure 91°, 46°, and 119°.

Mathematics
1 answer:
atroni [7]3 years ago
6 0
Correct answer is C 104
jUST SEE ATACMENT  WHICH i SEND TO YOU

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What is the domain and range <br> f(x)=x^3
Wittaler [7]

Answer:

Step-by-step explanation:

The domain is X value and range is Y so just put y=x^3 in desmos and the graph appears then check its range and domain from it. the range is positive and nevative infinity

6 0
3 years ago
I need help
dangina [55]

Answer:

a)  x =3 and x=5

c)  x =-1 and x = \frac{-7}{3}

i)  x =0 and  x = \frac{-9}{2}

Step-by-step explanation:

a)

Given that the quadratic equation

    x² - 8x +15 =0

The factors of 15 = 5 × 3

   x² - 5x -3x +15 =0

  x(x -5) -3(x-5) =0

  (x-3)(x-5) =0

x =3 and x=5

c)

  3 x² + 10 x +7 =0

⇒   3x² + 3x + 7x +7 =0

⇒   3x (x +1) +7(x+1) =0

⇒  (x+1) ( 3 x +7) =0

⇒  x =-1 and x = \frac{-7}{3}

i)

     2 x ² + 9 x =0

⇒ x( 2 x + 9) =0

⇒ x =0 and 2 x = -9

⇒ x =0 and  x = \frac{-9}{2}

4 0
3 years ago
Evaluate the surface integral. s y ds, s is the helicoid with vector equation r(u, v) = u cos(v), u sin(v), v , 0 ≤ u ≤ 6, 0 ≤ v
Juliette [100K]

Compute the surface element:

\mathrm dS=\|\vec r_u\times\vec r_v\|\,\mathrm du\,\mathrm dv

\vec r(u,v)=(u\cos v,u\sin v,v)\implies\begin{cases}\vec r_u=(\cos v,\sin v,0)\\\vec r_v=(-u\sin v,u\cos v,1)\end{cases}

\|\vec r_u\times\vec r_v\|=\sqrt{\sin^2v+(-\cos v)^2+u^2}=\sqrt{1+u^2}

So the integral is

\displaystyle\iint_Sy\,\mathrm dS=\int_0^\pi\int_0^6u\sin v\sqrt{1+u^2}\,\mathrm du\,\mathrm dv

=\displaystyle\left(\int_0^\pi\sin v\,\mathrm dv\right)\left(\int_0^6u\sqrt{1+u^2}\,\mathrm du\right)

=\dfrac23(37^{3/2}-1)

4 0
3 years ago
Right answer gets brainlist
nadezda [96]

Answer:

19

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
PLEASE HELP AND EXPLAIN, URGENT, 98 POINTS
kap26 [50]

Answer:

B because it represents the lowest value

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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