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a_sh-v [17]
3 years ago
15

A quadrilateral has angles that measure 91°, 46°, and 119°.

Mathematics
1 answer:
atroni [7]3 years ago
6 0
Correct answer is C 104
jUST SEE ATACMENT  WHICH i SEND TO YOU

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How many solutions is 8x+47=8(x+5)
expeople1 [14]
8x + 47 = 8x + 40

No solutions  (the above 2 expressions cannot be equal for any value of x)
7 0
3 years ago
Read 2 more answers
What is the distance between points v (3,3) and w (-2,-3) round to the nearest tenth if necessary
Vinil7 [7]

Answer:

7.81 u

Step-by-step explanation:

<u>Given :- </u>

  • Two points (3,3) and (-2,-3) is given to us.

And we need to find out the distance between the two points . So , here we can use the distance formula to find out the distance. As,

:\implies D = √{(x2-x1)² + (y2-y1)²}

:\implies D =√[ (3+2)² +(-3-3)²]

:\implies D =√[ 5² +6²]

:\implies D =√[ 25 +36]

:\implies D = 61

:\implies D = 7.81

<h3>Hence the distance between the two points is 7.81 units .</h3>
6 0
3 years ago
The highest scorer of the​ women's basketball championship was Jessica Bradley. She scored more points than Tina​ Harner, her te
Arisa [49]

Answer:

Jessica Bradley - 856 Points

Tina​ Harner - 707 Points

Step-by-step explanation:

FULL QUESTION:

The highest scorer of the​ women's basketball championship was Jessica Bradley. She scored 149 more points than Tina​ Harner, her teammate.​ Together, Bradley and Harner scored 1563 points. How many points did each player score during the​ championship?

Let T = points scored by Tina Harner

     J = points scored by Tina Harner

She scored 149 more points than Tina​ Harner, her teammate.​ This means;

J = T + 149...........(i)

Together, Bradley and Harner scored 1563 points. This means;

J + T = 1563 .........(ii)

How many points did each player score during the​ championship?

We have to find T and J.

Substitute value of J from eqn (i) into eqn (ii)

T + 149 + T = 1563

2T = 1563 - 149 = 1414

T = 1414 / 2 = 707

J = 707 + 149 = 856

Jessica Bradley - 856 Points

Tina​ Harner - 707 Points

3 0
3 years ago
The area of a rectangle is 27 m^2 , and the length of the rectangle is 3 m less than twice the width. Find the dimensions of the
vagabundo [1.1K]
Let L be the length of the rectangle and W be the width. In the problem it is given that L=2W-3. It is also given that the area LW=27. Substituting in the length in terms of width, we have W(2W-3)=27 \\ 2W^2-3W-27=0 \\ (2W-9)(W+3)=0. Using the zero product property, 2W-9=0 \text{ or } W+3=0. Solving these we get the width W=4.5 \text{ or } -3. However, it doesn't make sense for the width to be negative, so the width must be \boxed{4.5 \text{ m}}. From that we can tell the length L=2(4.5)-3=\boxed{6 \text{ m}}. 
3 0
3 years ago
Which of the following
Ronch [10]

Answer:

Option A

Step-by-step explanation:

<u>Given equation is</u>

=> 3y = 6x + 3

<u>In slope-intercept form, it becomes</u>

=> 3y = 3(2x+1)

=> y = 2x+1

So, Slope = m = 2

<u><em>Parallel lines have equal slope, So any line parallel to the above line would have its slope equal to 2</em></u>

=> Line parallel to 3y = 6x + 3 is y = 2x + 10

3 0
4 years ago
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