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gregori [183]
3 years ago
5

What is the product? 3x^5 (2x^2+4x+1)

Mathematics
2 answers:
s2008m [1.1K]3 years ago
8 0

Answer:

The product of the given polynomial 3x^5(2 x^2+4x+1)  is 6x^7+12x^6+3x^5

Step-by-step explanation:

Given: Polynomial 3x^5(2 x^2+4x+1)

We have to find the product of the given polynomial 3x^5(2 x^2+4x+1)

Consider the given polynomial 3x^5(2 x^2+4x+1)  

Apply distributive rule, a(b+c)=ab+ac

Multiply 3x^5 with each term in brackets, we have,

=3x^5\cdot \:2x^2+3x^5\cdot \:4x+3x^5\cdot \:1

=3\cdot \:2x^5x^2+3\cdot \:4x^5x+3\cdot \:1\cdot \:x^5

Apply exponent rule, a^b\cdot \:a^c=a^{b+c}

Simplify, we have,

=6x^7+12x^6+3x^5

Thus, The product of the given polynomial 3x^5(2 x^2+4x+1)  is 6x^7+12x^6+3x^5

almond37 [142]3 years ago
5 0
<span><span>the answer is C.) 6x^7...
  </span></span>
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Answer:

Tan C = 3/4

Step-by-step explanation:

Given-

∠ A = 90°, sin C = 3 / 5

<u>METHOD - I</u>

<u><em>Sin² C + Cos² C = 1</em></u>

Cos² C = 1 - Sin² C

Cos² C = 1 - \frac{9}{25}

Cos² C = \frac{25 - 9}{25}

Cos² C = \frac{16}{25}

Cos C = \sqrt{\frac{16}{25} }

Cos C = \frac{4}{5}

As we know that

Tan C = \frac{Sin C}{Cos C }

<em>Tan C = \frac{\frac{3}{5} }{\frac{4}{5} }</em>

<em>Tan C = \frac{3}{4}</em>

<u>METHOD - II</u>

Given Sin C = \frac{3}{5} = \frac{Height}{Hypotenuse}

therefore,  

AB ( Height ) = 3; BC ( Hypotenuse) = 5

<em>∵ ΔABC is Right triangle.</em>

<em>∴ By Pythagorean Theorem-</em>

<em>AB² + AC² = BC²</em>

<em>AC² </em><em>= </em><em>BC² </em><em>- </em><em> AB</em><em>² </em>

<em>AC² = 5² - 3²</em>

<em>AC² = 25 - 9</em>

<em>AC² = 16</em>

<em>AC  ( Base) = 4</em>

<em>Since, </em>

<em>Tan C = \frac{Height}{Base}</em>

<em>Tan C = \frac{AB}{AC}</em>

<em>Hence Tan C = \frac{3}{4}</em>

<em />

4 0
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