We have been given that in ΔHIJ, the measure of ∠J=90°, the measure of ∠I=29°, and JH = 88 feet. We are asked to find the length of IJ to the nearest tenth of a foot.
First of all, we will draw a right triangle using our given information as shown in the attachment.
We can see that in triangle HIJ, the side IJ is adjacent side to angle I and JH is opposite side to angle I.
We know that tangent relates opposite side of right triangle to adjacent side.
Upon rounding to nearest tenth, we will get:
Therefore, the length of the side IJ is approximately 258.8 units.
As 300 tickets are sold , the probability of being a winner is = 
The prize value is $64 or 
= 0.213
The cost of ticket you paid = $4
Hence, the expected value of one ticket = 0.213-4 = -3.787 or rounding off we get -3.79
<h3><u>Given</u>:</h3>
- A rectangle has a height of 4 and a width of x² + 3x + 2.
<h3><u>To find</u>:</h3>
- The area of the entire rectangle.
<h3><u>Solution</u>:</h3>
Hence, we know that area of rectangle is equals to the product of length and breadth.
Therefore, the area of rectangle is,
Therefore, the answer is 4x² + 12x + 8.
Answer:
1.57 radians
Step-by-step explanation:
Divide both sides by 360, you get 1° = π/180. This means 70° is equal to (70)(π/180). Then simplify this, and 70° = (7π)/18 radians, or approximately 1.221730476396 radians. This seems reasonable because 90°, is a quarter circle and (1/4) of 2π is π/2, which is approximately 1.57 radians.
(20:4)x3=15 (Ellas grade)
(20:5)x4=16 (Minhs grade)
