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gregori [183]
3 years ago
5

What is the product? 3x^5 (2x^2+4x+1)

Mathematics
2 answers:
s2008m [1.1K]3 years ago
8 0

Answer:

The product of the given polynomial 3x^5(2 x^2+4x+1)  is 6x^7+12x^6+3x^5

Step-by-step explanation:

Given: Polynomial 3x^5(2 x^2+4x+1)

We have to find the product of the given polynomial 3x^5(2 x^2+4x+1)

Consider the given polynomial 3x^5(2 x^2+4x+1)  

Apply distributive rule, a(b+c)=ab+ac

Multiply 3x^5 with each term in brackets, we have,

=3x^5\cdot \:2x^2+3x^5\cdot \:4x+3x^5\cdot \:1

=3\cdot \:2x^5x^2+3\cdot \:4x^5x+3\cdot \:1\cdot \:x^5

Apply exponent rule, a^b\cdot \:a^c=a^{b+c}

Simplify, we have,

=6x^7+12x^6+3x^5

Thus, The product of the given polynomial 3x^5(2 x^2+4x+1)  is 6x^7+12x^6+3x^5

almond37 [142]3 years ago
5 0
<span><span>the answer is C.) 6x^7...
  </span></span>
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Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{0}}}}}

Step-by-step explanation:

\sf{ [ (4 \frac{1}{6}  + 2 \frac{1}{3} )  \div 4 \frac{1}{3}] -  1\frac{1}{2} }

Convert the mixed numbers into improper fraction

\longrightarrow{ \sf{ [ ( \frac{25}{6}  +  \frac{7}{3} ) \div  \frac{13}{3}] -  \frac{3}{2}}}

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While performing addition or subtraction of unlike fractions, you have to express the given fractions into equivalent fractions of common denominator and add or subtract as we do with like fraction.

To do so, first take the L.C.M of 6 and 3 which results to 6

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Multiply the dividend by the reciprocal of the divisor.

Reciprocal of any number or fraction can be obtained by interchanging the position of numerator and denominator

\longrightarrow{ \sf{ [  \frac{39}{6}  \times  \frac{3}{13} ] -  \frac{3}{2}}}

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While performing the addition or subtraction of like fractions , you just have to add or subtract the numerator respectively in which the denominator is retained same

\longrightarrow{ \sf{ \frac{3 - 3}{2} }}

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