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2 years ago

How many 10ths are in 2/5

Mathematics

2 answers:

Inga [223]2 years ago

5 0

Answer: 4

===============================

Work Shown:

2/5 = 4/10

since multiplying top and bottom of 2/5 by the value 2 leads to 4/10

The fraction 4/10 indicates there are 4 copies of "one-tenth"

guapka [62]2 years ago

3 0

Answer:

Step-by-step explanation:

2/5 = 4/10

Multiply the fraction (2/5) by (2/2)

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alukav5142 [94]

Answer:

Weight of the solution = 250 grams

Step-by-step explanation:

1) Consider the weight of solution as x grams.

32 % solution = 80 grams salt

32% of x = 80

(32/100)*x = 80

Solving for x:

x = (80*100) / 32

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3 years ago

1. -12x + 7 = 79 Please help me

LUCKY_DIMON [66]

Answer:

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Step-by-step explanation:

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3 years ago

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Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v

k0ka [10]

I'll use subscript notation for brevity, i.e. $\frac{\partial f}{\partial x}=f_x$ .

By the chain rule,

$z_u=z_xx_u+z_yy_u$

$z_v=z_xx_v+z_yy_v$

$z_w=z_xx_w+z_yy_w$

We have

$z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}$

and

$\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}$

When $u=1,v=1,w=0$ , we have

$\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}$

and the partial derivatives take on values of

$\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}$

So we end up with

$\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}$

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2 years ago

Find the slope of the line through each pair of points. (- 12, 20 ). ( 15 ,- 12)

gtnhenbr [62]

Answer:

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Step-by-step explanation:

-12 - 20 -32 -32

----------- = ----------- = ----------

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2 years ago

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Minchanka [31]

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$\boxed{\bold{Eclipsed}}$

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3 years ago