Question

Pd). cot x/sec x show that -=cos ecx -sin x​

Answer 1

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

• cot x = $\frac{cosx}{sinx}$

• sec x = $\frac{1}{cosx}$ and cosec x = $\frac{1}{sinx}$

Consider the left side

$\frac{cotx}{secx}$

= $\frac{cosx}{sinx}$ × cosx

= $\frac{cos^2x}{sinx}$

= $\frac{1-sin^2x}{sinx}$

= $\frac{1}{sinx}$ - $\frac{sin^2x}{sinx}$

= cosec x - sin x

= right side ⇒ verified