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Ksivusya [100]
3 years ago
13

A school has a parking lot that is 150.23 feet by 135.12 feet. What is the perimeter of the parking lot?

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
4 0

Answer: 570.70 ft

Step-by-step explanation:

The perimeter is the distance around the entire parking lot.

The measurement of 150.23 ft by 135.12 ft is half of the distance of the lot because it represents just two sides yet there are 4 sides.

The other two sides have the same measurement as this is a rectangle.

The perimeter of the parking lot is:

= (150.23 * 2) + (135.12 * 2)

= 570.70 ft

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meriva
Hi!
This is a fun one, as it delves into basic trigonometry.

We're going to use the Pythagorean theorem here, which says that for right triangles where "c" is the hypotenuse,

a² + b² = c²

We have to split this large triangle into two parts, both of which are right triangles. (This is why they drew a line in the middle to tell you that the larger triangle is composed of two right triangles.)

Let's do the one on the right first.

We know that the length of the hypotenuse is 10, and that the length of one of the legs is 6.5. If we plug this into our equation, we'll get the length of the other leg. I'm choosing "b" to be 6.5, but it really doesn't matter if you pick "a" or "b", so long as you reserve "c" for the hypotenuse (longest side).

a² + 6.5² = 10²
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Therefore, the length of DC is about 7.6.

Find the length of AD using the same method (7.5 is the hypotenuse "c", and 6.5 is one of the legs "a" or "b"). Then, once you have AD, add the lengths of AD and DC to get AC.

Have a great one!
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3 years ago
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