3 tan³ t(theta) = tan t(theta)
3 tan³ t - tan t = 0
tan t ( 3 tan² t - 1 ) = 0
tan t = 0
t 1 = k π , k ∈ Z
3 tan ² t - 1 = 0
3 tan ² t = 1
tan ² t = 1/3
tan t = +/- √3/3
t 2 = π / 6 + k π
t 3 = - π / 6 + k π , k ∈ Z
Replace the x with 2: f(2)=2*2+7=4+7=11
replace the x with 7: f(7)=2*7+7=14+7=21
Answer:
∠FJH ≅ ∠BJA
Step-by-step explanation:
From the image we can see that the only congruent relation ∠FJH has is with ∠BJA which is due to these angles being vertically opposite
So, ∠FJH and ∠BJA are vertically opposite and hence, congruent. We can say that ∠FJH ≅ ∠BJA
The answer is 16 ft because 6 ft tall over 4 feet 6 inches (4.5) is equal to x (tree's height) over 12 ft. You cross multiple and get 72 = 4.5x then you take 72 and divide by 4.5 to get the tree's height
