Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.
1. x = ?
2. m∠MKL = ?
3. m∠JKL = ?
Answer/Step-by-step explanation:
Given:
m<JKM = 43,
m<MKL = (8x - 20),
m<JKL = (10x - 11).
Required:
1. Value of x
2. m<MKL
3. m<JKL
Solution:
1. Value of x:
m<JKL = m<MKL + m<JKM (angle addition postulate)
Therefore:
Solve for x
Subtract 8x from both sides
Add 11 to both sides
Divide both sides by 2
2. m<MKL = 8x - 20
Plug in the value of x
m<MKL = 8(17) - 20 = 136 - 20 = 116°
3. m<JKL = 10x - 11
m<JKL = 10(17) - 11 = 170 - 11 = 159°
Answer:
Step-by-step explanation:
It can't be 102. If that happened 51 would be printer and you would never have gotten out of 51. It would keep on printing 51.
For the reason just given, 51 was not the starting point. It would just keep on printing 51.
D is obviously wrong because A and B are wrong.
The answer is C
204 is even. It will be divided by 2
102 is then printed out.
Answer: What you must do for this case is to graph each of the ordered pairs that you have in the table to obtain the dispersion chart. Note that in your table you have eight ordered pairs, therefore, your scatter chart must have eight pairs.
Step-by-step explanation:
The domain is related to the x-value of the function. In this case, the goal of finding the domain is to make sure that the number under the radical sign is positive. The number that makes the function under the radical sign is -2. Hence this is the minimum number and the domain is from -2 to positive infinity.
