To determine whether a cell is a eukaryotic or
prokaryotic cell, one can observe certain features.
If the cell in the question possesses a well-defined
or definite nucleus and have membrane-bound
organelles such as mitochondria, chloroplasts,
Golgi apparatus, endoplasmic reticulum, the cell is
eukaryotic. If the cell has nucleoid or indefinite
nucleus and without membrane-bound cell
organelles, the cell is prokaryotic. If ribosomes in
a cell are the 80S (S=Svedberg units) type, the cell
is eukaryotic and if ribosomes are 70S type then it
is prokaryotic.
"Larva" is a stage in the life cycle of an insect among the following choices given in the question that a <span>caterpillar represents. The correct option among all the options that are given in the question is the second option or option "B". I hope that this is the answer that has actually come to your desired help.</span>
This is false. DNA transcription is the first step in gene expression.
Answer:
1/8
Explanation:
Given that the trihybrid parents have AaBbCc genotype for fruit color. The trait is a quantitative trait i.e. each dominant allele will have an additive effect on it. In this case, AaBbCc and AABBCC will not produce same fruit color because AaBbCc has only three loci contributing to the color while in AABBCC all the six loci are contributing to the color. For an offspring to be exactly similar to the AaBbCc parents it should have the same genotype of AaBbCc.
The probability of Aa to come from a cross between Aa and Aa is 2/4 or 1/2
The probability of Bb to come from a cross between Bb and Bb is 2/4 or 1/2
The probability of Cc to come from a cross between Cc and Cc is 2/4 or 1/2
So the collective probability of AaBbCc offspring from a cross between AaBbCc and AaBbCc parents would be=
1/2 * 1/2 * 1/2 = 1/8
Hence, assuming no effects of the environment, 1/8 of the offspring will have the same fruit color phenotype as the trihybrid parent.
