1/8 is tha answer............
Answer:
a. no solution
Step-by-step explanation:
y=5x-4
y=5x-5
so
5x - 4 = 5x - 5
-4 ≠ -5
No solution
Is D because you set x to 0 or you set y to 0, if you set x to 0 then y will be 5. (X,5) so is D
Answer:
A. 320
Step-by-step explanation:
See attachment for the figure
in order to determine Area of quadrilateral ABDF, we'll use the formula i.e
Area of quadrilateral ABDF = Area of AECD - Area of ΔBCD - Area of ΔDEF ->eq(1)
whereas, area of AECD = (AC × AE)
Area of ΔBCD = 1/2 (BC x CD)
Area of ΔDEF =1/2 ( EF x ED)
Substituting in eq(1)
eq(1)=>
Area of quadrilateral ABDF = (AC × AE) - 1/2 (BC x CD)- 1/2 ( EF x ED)
=(32 x 20) - 1/2(16 x 20) - 1/2(10 x 32)
= 640 - 160 - 160
= 640 - 320
= 320 square unit
Therefore, the area of quadrilateral ABDF is 320 square unit
Step-by-step explanation:
it's answer is c 23
Step-by-step explanation:
Here
The lines are parallel so
3x + 28° + 2x + 37° = 180°<being co-interior angles>
5x + 65° = 180°
5x = 180° - 65°
5x = 115°
Therefore x = 23°