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DENIUS [597]
3 years ago
6

How do u do this.I need major help on it

Mathematics
1 answer:
Tpy6a [65]3 years ago
4 0
Look for what 'y' is when t = 1 and t = 2. Go to the graph, look at 1 on the bottom axis and go up till you find the point, then go all the way to the left to see what the y-value is, in this case it should be 1200. If you do the same with t = 2, you will get 2400. So our two ordered pairs are:

(1, 1200), (2, 2400)

We can find the slope of these two points by plugging them into the slope formula:

\sf m=\dfrac{y_2-y_1}{x_2-x_1}

For points in the form of (x1, y1), (x2, y2). Plug in what we know:

\sf m=\dfrac{2400-1200}{2-1}

Subtract:

\sf m=\dfrac{1200}{1}

Divide:

\sf m=1200

This is the slope, so we can write the equation:

\boxed{\sf y=1200t}
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Length + width = 1/2 the perimeter:30/2 = 15

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List the factors of 50: 1, 2, 5, 10, 25, 50.

Find the two factors that when added together equal 15:

Dimensions are 5 cm by 10 cm.

6 0
2 years ago
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SSSSS [86.1K]

The answer to this question is 10 cm

In this question, you asked the height and given the volume of water(2400cm3), aquarium length(20cm), and aquarium width(12cm).

Then you need to divide the volume with the length and width. The equation would be:

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Aquarium height= 2400 cm3 / 20cm / 12 cm = 10cm.

7 0
3 years ago
How do you find the derivative of 1/logx?
valentina_108 [34]

The derivative of 1/logx is With the chain rule.

1log(x)=log(x)−1 is ,= -1xlog(x)2 .

The by-product of logₐ x (log x with base a) is 1/(x ln a). Here, the thrilling issue is that we have "ln" withinside the by-product of "log x". Note that "ln" is referred to as the logarithm (or) it's miles a logarithm with base "e".

The by-product of 1/log x is -1/x(log x)^2. Note that 1/logx is the reciprocal of log.

With the chain rule. \\ 1log(x)=log(x)−1  \\ So you follow the chain rule to the electricity after which to the log: \\ ddxlog(x)−1=−1⋅log(x) \\  \\−2⋅ddxlog(x)  \\ =−1log(x)21x  \\ =−1xlog(x)2 .

Read more about derivatives;

brainly.com/question/23819325

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5 0
1 year ago
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VladimirAG [237]

So first thing we have to realise is that we have to make them have equal denominators. So,

\frac{1}{6} =  \frac{4}{24}  \\ \\   \frac{1}{8} =  \frac{3}{24}  \\  \\  \frac{1}{3} =  \frac{8}{24}.

Now order the fractions....so,

\frac{1}{3} = \frac{8}{24}  \\  \\ \frac{1}{6} = \frac{4}{24} \\ \\ \frac{1}{8} = \frac{3}{24}

Now we can see why \frac{1}{6} is greater than \frac{1}{8} but less than \frac{1}{3} 

5 0
3 years ago
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Answer:

362=271w

Step-by-step explanation:

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Hope this helps!

4 0
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