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balu736 [363]
3 years ago
14

If the complex number x = 3 + bi and |x| 2 = 13, which is a possible value of b?

Mathematics
1 answer:
tatyana61 [14]3 years ago
5 0

Answer:

A.2

Step-by-step explanation:

We know that |x|² = 13 and x = 3+bi:

(3+bi)² = 13

3² + b² = 13

9 + b² = 13

Subtract 9 from each side:

9 + b² - 9 = 13 - 9

b² = 4

Take the square root of each side:

√b² = √4

b = 2

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Degger [83]

Answer:

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Step-by-step explanation:

Given in the question,

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To find,

show working

<h3>Explanation</h3>

As we know that to divide exponents (or powers) with the same base, we subtract the exponents. Division is the opposite of multiplication, so when multiplying the exponents (or powers) with the same base add the exponents.

<h3>Working</h3>

a^5 * a^4 / a²

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= a^7  

<em>hence shown</em>

8 0
3 years ago
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anzhelika [568]
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denis-greek [22]

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