Are you asking to factor it? if so, the answer is (x-6)(x^2+6x+36)
Remember the rules of Sohcahtoa (Sine, cosine, tangent). For this problem we take the cosine of 38 because the labeled sides are the adjacent leg and the hypotenuse.
Cos(38)=79/x
Cosine of 38 is about 0.7880
0.7880=79/x
Next we multiply both sides by the denominator
(x) 0.7880=79 (x)
Then divide.
<u>0.7880x</u>= <u>79</u>
0.7880 0.7880
X=100.25
Hope this helped :)
Answer:
5%
Step-by-step explanation:
Total 'halwa' made = 1
Divided into four equal portion = 1/4
Arrival of an unexpected guest = 1/5
By what percentage has each family member's share been reduced:
Change in the sharing proportion:
Previous share ratio - new sharing ratio
(1/4 - 1/5) = (5 - 4) / 20 = 1/20
That means total reduction in the sharing = 1/ 20
Since each member comes contributed equally:
Reduction in each family member's share ;
(1 / 20) ÷ 4
(1 / 20) * 1/4 = 1/ 80
Percentage reduction:
(Reduction / original share) * 100%
[(1/80) ÷ (1/4)] * 100
(1/80 * 4/1) * 100%
(1/20) * 100%
= 5%
Reduction in each family members share = 5%
Answer:
The mean is the average you're used to, where you add up all the numbers and then divide by the number of numbers. The median is the middle value in the list of numbers. The mode is the value that occurs most often.
Answer:
Follows are the solution to this question:
Step-by-step explanation:
In the given question some of the data is missing so, its correct question is defined in the attached file please find it.
Let
A is quality score of A
B is quality score of B
C is quality score of C
![\to P[A] =0.55\\\\\to P[B] =0.28\\\\\to P[C] =0.17\\](https://tex.z-dn.net/?f=%5Cto%20P%5BA%5D%20%3D0.55%5C%5C%5C%5C%5Cto%20P%5BB%5D%20%3D0.28%5C%5C%5C%5C%5Cto%20P%5BC%5D%20%3D0.17%5C%5C)
Let F is a value of the content so, the value is:
![\to P[\frac{F}{A}] =0.15\\\\\to P[\frac{F}{B}] =0.12\\\\\to P[\frac{F}{C}] =0.14\\](https://tex.z-dn.net/?f=%5Cto%20P%5B%5Cfrac%7BF%7D%7BA%7D%5D%20%3D0.15%5C%5C%5C%5C%5Cto%20P%5B%5Cfrac%7BF%7D%7BB%7D%5D%20%3D0.12%5C%5C%5C%5C%5Cto%20P%5B%5Cfrac%7BF%7D%7BC%7D%5D%20%3D0.14%5C%5C)
Now, we calculate the tooling value:
![\to p[\frac{C}{F}]](https://tex.z-dn.net/?f=%5Cto%20p%5B%5Cfrac%7BC%7D%7BF%7D%5D)
using the baues therom:
