How to find the value of x and y on a transversal

Mathematics

1 answer:

irina1246 [14]2 years ago

4 0

Answer:

b is the value of the function when x equals zero or the y-coordinate of the point where the line crosses the y-axis in the coordinate plane. x is the value of the x-coordinate. This form is called the slope-intercept form.

Step-by-step explanation:

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Jill can run a mile in 8 minutes. write an expression that represents the time it takes her to run m miles.

shtirl [24]

Hello,

The answer should be "8=m".

Reason:

Since it takes 8 minutes to run 1 mile put that first:

8

Since how 8min equal 1 mile you put equal

8=

Since how it could be more miles but m

8=m

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3 years ago

X-23 / x^2 -x- 20 - 2/5-x

alexira [117]

By simplifying $x - \frac{{23}}{{{x^2}}} - x - 20 - \frac{2}{5} - x$ . This will result in a simplified version of $- \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}$ .

The Simplifying Algorithm is a wonderful way to simplify complex mathematics problems. It can be used to solve equations, convert fractions to decimals, and perform many other math operations. In this problem, the Simplifying Algorithm will help you reduce $x - \frac{{23}}{{{x^2}}} - x - 20 - \frac{2}{5} - x$

Since two opposites add up to 0, remove them from the expression.

$- \frac{{23}}{{{x^2}}} - \frac{{102}}{5} - x$

Write all numerators above the least common denominator 5x2

$- \frac{{115 + 102{x^2} + 5{x^3}}}{{5{x^2}}}$

Use the commutative property to reorder the terms so that constants on the left

$\frac{{ - 5{x^3} - 115 - 102{x^2}}}{{5{x^2}}}$

Rearrange the terms

$\frac{{ - 5{x^3} - 102{x^2} - 115}}{{5{x^2}}}$

By reording the terms

$- \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}$

Hence, by simplifying this equation, divide both numerator and denominator. This will result in a simplified version of $- \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}$ .

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Lyrx [107]

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Step-by-step explanation:

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