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Zinaida [17]
3 years ago
12

Will mark brainliest

Mathematics
1 answer:
MrMuchimi3 years ago
5 0

Answer:

i think addition

..........

Step-by-step explanation:

.

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Find the 53rd multiple of 62, if the 54th multiple is 3348.
Scorpion4ik [409]

Answer:

\displaystyle 3286

Explanation:

Just multiply 62 and 53 to get 3286.

I am joyous to assist you at any time.

4 0
2 years ago
-5x + 3(7x - 5)<br> Help???
Anna007 [38]
So here we just are gonna distribute and simplify.

7 0
3 years ago
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I need help with number 8
murzikaleks [220]
Since we know what he earns hourly, and his sales, we can figure out his full gross pay for the week.
As so:

We can set up an equation like this:
<em>h</em> = hours
<em>s</em> = sales
9.60h + 5%s

Now, we substitute.
9.60(35) + 5%(230)

Next, solve.
336.00 + 11.50
$347.50

$347.50 was Glen's gross pay for the week.

Hope I could help! If my math is wrong, or I did not provide the answer you were looking for, let me know! However, if I did well, please consider marking as <em>Brainliest!
</em>Have a good one!

8 0
3 years ago
Read 2 more answers
Sectionalizing formula of 2<img src="https://tex.z-dn.net/?f=%5Csqrt%7B3%7D" id="TexFormula1" title="\sqrt{3}" alt="\sqrt{3}" al
kozerog [31]

Answer:

\sqrt{3 \times 2 {?}^{2} }  =   \sqrt{12}  = 3.46

3 0
3 years ago
The volume (in cubic inches) of a shipping box is modeled by V =2x³ -19x² +39x, where x is the length (in inches). Determine the
yawa3891 [41]

Answer:

The values of x for which the model is 0 ≤ x ≤ 3

Step-by-step explanation:

The given function for the volume of the shipping box is given as follows;

V = 2·x³ - 19·x² + 39·x

The function will make sense when V ≥ 0, which is given as follows

When V = 0, x = 0

Which gives;

0 = 2·x³ - 19·x² + 39·x

0 = 2·x² - 19·x + 39

0 = x² - 9.5·x + 19.5

From an hint obtained by plotting the function, we have;

0 = (x - 3)·(x - 6.5)

We check for the local maximum as follows;

dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0

6·x² - 38·x + 39 = 0

x² - 19/3·x + 6.5 = 0

x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2

∴ x = 1.288, or 5.045

At x = 1.288, we have;

V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99

V ≈ 22.99 in.³

When x = 5.045, we have;

V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023

Therefore;

V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5

The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.

8 0
3 years ago
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