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Delicious77 [7]
3 years ago
8

A polynomial functiion P(x) with rational coefficients has the given roots. find two additional roots of p(x)=0

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
8 0
If -2i is a root, then 2i is also a root. If √10 is a root, then -√10 is also a root. Convert all four of these roots into factors using the factor theorem (which says that if R is a root, then (x - R) is a factor). (x + 2i) (x - 2i) (x - √10) (x + √10) Multiply these factors together. (It's easiest to multiply the conjugate pairs together first.): x^4 - 6x^2 - 40
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Evaluate (-2 4/5)-(-1 5/6)​
iragen [17]

Answer:

(-29)/30

Step-by-step explanation:

Simplify the following:

-(2 + 4/5) + (1 + 5/6)

Put 2 + 4/5 over the common denominator 5. 2 + 4/5 = (5×2)/5 + 4/5:

-(5×2)/5 + 4/5 + 1 + 5/6

5×2 = 10:

-(10/5 + 4/5) + 1 + 5/6

10/5 + 4/5 = (10 + 4)/5:

-(10 + 4)/5 + 1 + 5/6

10 + 4 = 14:

-14/5 + 1 + 5/6

Put (-14)/5 + 1 + 5/6 over the common denominator 30. (-14)/5 + 1 + 5/6 = (6 (-14))/30 + 30/30 + (5×5)/30:

(6 (-14))/30 + 30/30 + (5×5)/30

6 (-14) = -84:

(-84)/30 + 30/30 + (5×5)/30

5×5 = 25:

(-84)/30 + 30/30 + 25/30

-84/30 + 30/30 + 25/30 = (-84 + 30 + 25)/30:

(-84 + 30 + 25)/30

| 3 | 0

+ | 2 | 5

| 5 | 5:

(55 - 84)/30

55 - 84 = -(84 - 55):

(-(84 - 55))/30

| 7 | 14

| 8 | 4

- | 5 | 5

| 2 | 9:

Answer: (-29)/30

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