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3 years ago

7y^2+15x-22. Y=4. ×=5

Mathematics

1 answer:

Nutka1998 [239]3 years ago

3 0

let's plug the value of x and y as 5 and 4 respectively to find the value of given expression :

$7 {y}^{2} + 15x - 22$

$7(4) {}^{2} + (15 \times 5) - 22$

$(7 \times 16) + 75 - 22$

$112 + 53$

$165$

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The formula F=9/5C+32 converts temperatures from Celsius C to Fahrenheit F. A. Solve the formula for C b. The boiling point of w

liraira [26]

Answer:

(a) $\therefore C=\frac59(F-32)$

(b)The boiling point of water in Celsius scale is 100°C.

(c)The setting in Celsius scale is 26.7°C.

Step-by-step explanation:

Given that,the formula is

$F=\frac95 C+32$ ......(1)

(a)

Given that,

$F=\frac95 C+32$

$\Rightarrow F-32=\frac95 C+32-32$ [ subtracting 32 from both sides]

$\Rightarrow F-32=\frac95 C$

$\Rightarrow \frac95 C=F-32$

$\Rightarrow C=\frac59(F-32)$ ......(2) [Multiplying $\frac59$ ]

$\therefore C=\frac59(F-32)$

(b)

Given that, the boiling point of water is 212°F.

Putting F=212 in equation (2)

$\therefore C=\frac59(212-32)$

$\Rightarrow C=\frac59\times 180$

$\Rightarrow C=5\times 20$

$\Rightarrow C=100$

The boiling point of water is 100°C.

(c)

Given that, a house thermostat is set at 80 degree.

Putting F=80 in equation (2)

$\therefore C=\frac59(80-32)$

$\Rightarrow C=\frac59\times 48$

$\Rightarrow C\approx26.7$

The setting in Celsius scale is 26.7°C.

7 0

3 years ago

Help plz this is due late so plz help me

Gekata [30.6K]

Answer:

1st option

Step-by-step explanation:

Each exponent inside the bracket is multiplied by the exponent outside , that is

$(\frac{2^{5} }{3^{2} )} ^{4}$

= $\frac{2^{5(4)} }{3^{2(4)} }$

= $\frac{2^{20} }{3^{8} }$

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3 years ago

What is (2n+2n)-(3n-4n)

Yakvenalex [24]

Answer:

2n^{2} +2n

INSERT

Step-by-step explanation:first you want to move the negative which is negative 1 into the set of parenthesis and then Foil the two parenthesis together and the combine like terms

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3 years ago

Asymptotes of x=3 and y=-2

dimaraw [331]

Answer:

Both of these values don't have asymptotes.

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3 years ago

Read 2 more answers

A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.

tatyana61 [14]

Answer:

(a) $g(n)=0.05\cdot 2^n$

(b) $g^{-1}(n)=\log_{2}20g(n)$

Step-by-step explanation:

Part A

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

$g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n$

Part B

$g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)$

Part C

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

$g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43$

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

3 0

3 years ago