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3 years ago

In the right trange show, A=30 degrees and AC=12 How long is AB

Mathematics

1 answer:

Levart [38]3 years ago

4 0

Answer:

$AB=6\sqrt{3}$

Step-by-step explanation:

$Given\ \angle A=30\textdegree\\\\AC=12\\\\\cos \theta=\frac{adjacent}{hypotenuse}\\\\\cos A=\frac{AB}{AC}\\\\\cos 30=\frac{AB}{12}\\\\\frac{\sqrt{3}}{2}=\frac{AB}{12}\\\\AB=6\sqrt{3}$

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10.) Fishermen have been studying how the number of dead sea turtles in the local bay is related to the pollution index of the b

alexdok [17]

Answer:

Step-by-step explanation:

A linear function is a polynomial function of the first degree that has the form:

f (x) = m*x + b or y=m*x + b

where y is the dependent variable, x is the independent variable, m is the slope of the line and b is the intercept with the Y axis.

The slope m measures the inclination of the line with respect to the abscissa axis, that is, the x axis. According to the value of the slope m, the linear function can be increasing if m> 0, decreasing if m <0 or constant if m = 0.

You know that the number of sea turtle deaths per year is modeled by f(x) = 13.42x + 109.118. Then the value of the slope is 13.42. In this scenario, the slope indicates that the number of deaths of sea turtles grows in a proportion of 13.42 with respect to the pollution index of the bay.

5 0

3 years ago

I neeed the answer now

natka813 [3]

Answer:

48 laps

Step-by-step explanation:

multiply 6 by 8 then that's your answer

4 0

3 years ago

Determine the measure of each indicated angle. Show all necessary steps!

Mariana [72]

The measure of the unknown angle are; a) x = 89 degrees, b) p = 92 degrees.

<h3>What is the sum of all the angles of a regular polygon?</h3>

For a regular polygon of any number of sides, the sum of its exterior angle is 360°.

We already know that a 4-sided polygon's angles add up to 360 degrees.

So to find the value of x:

69 + 118 + 84 + x = 360

x = 360 - (69 + 118 + 84)

x = 89 degrees

For a 4-sided polygon, we also know that the outside angles add up to 360 degrees.

So to find the value of p:

100 + 62 + 106 + p = 360

p = 360 - (100 + 62 + 106)

p = 92 degrees

Learn more about interior angles of a regular polygon here:

brainly.com/question/14173422

#SPJ1

7 0

2 years ago

solve for each please i really need help if u want to help me with my test and i get an a or a b i will give u 500 dollars

Len [333]

Answer:

The relation is not a function

The domain is {1, 2, 3}

The range is {3, 4, 5}

Step-by-step explanation:

A relation of a set of ordered pairs x and y is a function if

Every x has only one value of y

x appears once in ordered pairs

<u><em>Examples:</em></u>

The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)

The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)

The domain is the set of values of x

The range is the set of values of y

Let us solve the question

∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}

∵ x = 1 has y = 3

∵ x = 2 has y = 3

∵ x = 3 has y = 4

∵ x = 2 has y = 5

→ One x appears twice in the ordered pairs

∵ x = 2 has y = 3 and 5

∴ The relation is not a function because one x has two values of y

∵ The domain is the set of values of x

∴ The domain = {1, 2, 3}

∵ The range is the set of values of y

∴ The range = {3, 4, 5}

3 0

2 years ago

In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,

aivan3 [116]

Answer:

Case 1:

$AB = 30$

$BC = 50$

Case 2:

$AB = 15.9$

$BC = 36.7$

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

$AB^2 = AN^2 + BN^2$

This gives:

$AB^2 = 24^2 + 18^2$

$AB^2 = 576 + 324$

$AB^2 = 900$

Take square roots of both sides

$AB = \sqrt{900$

$AB = 30$

To calculate BC, we consider ANC, where:

$AC^2 = AN^2 + NC^2$

$40^2 = 24^2 + NC^2$

$1600 = 576 + NC^2$

Collect like terms

$NC^2 = 1600 - 576$

$NC^2 = 1024$

Take square roots

$NC = \sqrt{1024$

$NC = 32$

So:

$BC = NC + BN$

$BC = 32 + 18$

$BC = 50$

Case 2:

Using Pythagoras theorem in ANB, we have:

$AN^2 = AB^2 + BN^2$

This gives:

$24^2 = AB^2 + 18^2$

$576 = AB^2 + 324$

Collect like terms

$AB^2 = 576 - 324$

$AB^2 = 252$

Take square roots of both sides

$AB = \sqrt{252$

$AB = 15.9$

To calculate BC, we consider ABC, where:

$AC^2 = AB^2 + BC^2$

$40^2 = 252 + BC^2$

$1600 = 252 + BC^2$

Collect like terms

$BC^2 = 1600 - 252$

$BC^2 = 1348$

Take square roots

$BC = \sqrt{1348$

$BC = 36.7$

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

3 0

2 years ago