Answer:
line p matches with the first equation
Step-by-step explanation:
Answer:
Ques 16)
We have to simplify the expression:

Ques 17)

Ques 18)
Let the blank space be denoted by the quantity 'x'.

Ques 19)
Let the missing quantity be denoted by 'x'.

Assuming that there is no wastage of beef.
Note that 3 1/2 = 7/2 = 14/4 = 14 * 1/4
This means that we can have 14 sets of quarter pound beef.
This in turn means that George can make 14 quarter pound burgers.
speed =distance traveled over time taveled... the ansewr will be in kilometres per hour
Answer:
3. $600,000
Step-by-step explanation:
We have been given that a tenant rented a store to use as a real estate school at a base rent of $1,500 a month. Additionally, the tenant agreed to pay 3% of gross annual sales over $200,000.
Let us find base annual rent.

Let us find the amount of rent paid as 3% of gross annual sales.

Let us find amount of sales over $200,000 by dividing $12000 by 3% or 0.03.

Total sales would be $400,000 plus $200,000.

Therefore, the total sales for that year was $600,000 and 3rd option is the correct choice.