X² + 1 = 0
=> (x+1)² - 2x = 0
=> x+1 = √(2x)
or x - √(2x) + 1 = 0
Now take y=√x
So, the equation changes to
y² - y√2 + 1 = 0
By quadratic formula, we get:-
y = [√2 ± √(2–4)]/2
or √x = (√2 ± i√2)/2 or (1 ± i)/√2 [by cancelling the √2 in numerator and denominator and ‘i' is a imaginary number with value √(-1)]
or x = [(1 ± i)²]/2
So roots are [(1+i)²]/2 and [(1 - i)²]/2
Thus we got two roots but in complex plane. If you put this values in the formula for formation of quadratic equation, that is x²+(a+b)x - ab where a and b are roots of the equation, you will get the equation
x² + 1 = 0 back again
So it’s x=1 or x=-1
I don’t know I’m sorry I need points look it up on online
<u>Answer:</u>
The correct answer option is 'Every tenth student in the main hallway between class.'
<u>Step-by-step explanation:</u>
Every tenth student in the main hallway between class would best represent the sample population since majority of the students transit this hallway unlike the rest of the options.
For instance, polling every tenth student in the library at lunch would result in the favor of views of students who frequently visit the library and polling every tenth student in the student section at the school football game would go in favor of those who prefer sports.
9514 1404 393
Answer:
2) x = 7
3) x = 5
Step-by-step explanation:
When a transversal crosses parallel lines, all of the acute angles are congruent, and all of the obtuse angles are congruent. When it crosses at right angle, all of the angles are right angles.
2) All of the angles are right angles.
11x +13 = 90
11x = 77 . . . . . . subtract 13
x = 7 . . . . . . . divide by 11
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3) The two marked angles are acute.
16x = 80 . . . . the acute angles are congruent
x = 5 . . . . . . divide by 16
Answer:
(2,2)
Step-by-step explanation:
The graph of a function and that of its inverse should be always symmetric around the line y = x (goes at 45 degrees and crosses the origin of coordinates).
Therefore any intersection of the graphs must lie on the line y = x, which forces the x value of the intersection point to be the same as the y-value.
The only option shown where x and y have the same numerical value is the third listed option : (2,2)
