Answer:
The prove is as given below
Step-by-step explanation:
Suppose there are only finitely many primes of the form 4k + 3, say {p1, . . . , pk}. Let P denote their product.
Suppose k is even. Then P ≅ 3^k (mod 4) = 9^k/2 (mod 4) = 1 (mod 4).
ThenP + 2 ≅3 (mod 4), has to have a prime factor of the form 4k + 3. But pₓ≠P + 2 for all 1 ≤ i ≤ k as pₓ| P and pₓ≠2. This is a contradiction.
Suppose k is odd. Then P ≅ 3^k (mod 4) = 9^k/2 (mod 4) = 1 (mod 4).
Then P + 4 ≅3 (mod 4), has to have a prime factor of the form 4k + 3. But pₓ≠P + 4 for all 1 ≤ i ≤ k as pₓ| P and pₓ≠4. This is a contradiction.
So this indicates that there are infinite prime numbers of the form 4k+3.
Answer:
8x^2-2x-3/1+4x
Step-by-step explanation:
It doesn't say any of your answers but i just used a calculator and that's what i got
Sorry if its wrong
Answer:
- No, there is no proportional relationship
Step-by-step explanation:
<u>The proportional relationship is:</u>
- y = kx, which is a special form of linear equation, with zero y-intercept
<u>In the given case we have:</u>
This is a linear function but not proportional relationship because it has y-intercept, different than zero
(6m^2-2-5+m)-(3m-4+11m^2) =
<h2>
6m^2 - 2m - 124</h2>
Answer:
omg im still dont no
Step-by-step explanation:
sorry
