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4 years ago

Simplify the radical expression by rationalizing the denominator. 9√25/√50

Mathematics

2 answers:

vfiekz [6]4 years ago

7 0

Answer:

9/2√2 is correct.

Step-by-step explanation:

frozen [14]4 years ago

6 0

The denominator =
$5 \sqrt{2}$

numerator =
$45$

so, final answer is =
$\frac{9}{ \sqrt{2} }$

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Please help me on this and please show your work thank you:)

elena55 [62]

Start by turning the mixed number to an improper fraction by multiplying the 3 and 4 to get 12 and then add on 3 to that to get 15/4.
So not you have -2/3 ÷ 15/4. Do the reciprocal of 15/4 to get 4/15 and change the ÷ to a x (that's multiplication sign. After that multiply. -2/3 x 4/15 and the answer would be -8/45 :)

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3 years ago

What is the solution to the equation below? 3x + 29.5 = - 75.5

son4ous [18]

Answer:

x = − 35

Step-by-step explanation:

hope this helps

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3 years ago

Lim (8-3x+12x^2) x 2

kupik [55]

24x^2-6x+16 i think that is the answer..?

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3 years ago

The Pythagorean theorem is used to prove that a triangle is a(n) triangle.

sleet_krkn [62]

The Pythagorean theorem is used to prove that a triangle is a(n) _________triangle.

The Pythagorean theorem is used to prove that a triangle is a right triangle.

We also have Pythagorean triangle. This is known as primitive right triangle.

The used of the said theorem is to prove that the square on the hypotenuse of a right triangle is equal to the sum of the squares on the two legs. One of the studies said that the theorem is talking about the area of the squares that are built on each side of the right triangle.

4 0

3 years ago

The bad debt ratio for a financial institution is defined to the dollar value of loans defaulted divided by the total dollar val

vlabodo [156]

Answer:

Step-by-step explanation:

From the information given:

Consider X to be the random variable denoting the bad debt ratios for Ohio Bank.

Then, $X \sim N ( \mu, \sigma ^2)$

Thus the null hypothesis and the alternative can be computed as:

Null hypothesis:

$H_o : \mu \leq3.5\%$

Alternative hypothesis

$H_1 : \mu > 3.5\%$

The type I and type II error is as follows:

Type I:

The mean bad debt ratio is > 3.5% when it is not

Type II:

The mean bad debt ratio is ≤ 3.5% when it is not.

The test statistics can be calculated by using the formula:

$t = \dfrac{\overline x - \mu}{\dfrac{\sigma}{\sqrt{n}}}$

where;

sample size n = 7

mean = 6+8+5+9+7+5+8 = 48

sample mean $\overline x =\dfrac{48}{7}$

$\overline x$ = 6.86

sample standard deviation is :

$s = \sqrt{\dfrac{\sum( x -\overline x)^2}{n-1}}$

$s = \sqrt{\dfrac{( 6 -6.86)^2+( 8-6.86)^2+ ( 5 -6.86)^2 + ...+( 7 -6.86)^2+ ( 5 -6.86)^2+( 8 -6.86)^2 }{7-1}}$

s = 1.573

population mean $\mu = 3.5$

Therefore, the test statistics is :

$t = \dfrac{\overline x - \mu}{\dfrac{\sigma}{\sqrt{n}}}$

$t = \dfrac{6.86- 3.5}{\dfrac{1.573}{\sqrt{7}}}$

$t = \dfrac{3.36}{\dfrac{1.573}{2.65}}$

$t = \dfrac{3.36\times {2.65}}{{1.573}}$

t = 5.660

At significance level of 0.01

$t_{0.01} = 3.707$

P - value = P(T > 5.66)

P - value = 1 - (T < 5.66)

P - value = 1 - 0.9993

P-value = 0.0007

Therefore, since $t_{0.01} < t$ , we reject the null hypothesis and conclude that the claim that the mean bad debt ratio for Ohio banks is higher than the mean for all financial institutions is true.

4 0

4 years ago