Brian has 39 cards and Wesley has 48 cards
Step-by-step explanation:
Let w be the number of cards Wesley has
and
b be the number of cards Brian has
Then
![w+b = 87\ \ \ \ Eqn\ 1\\w = 2b-30\ \ \ Eqn\ 2](https://tex.z-dn.net/?f=w%2Bb%20%3D%2087%5C%20%5C%20%5C%20%5C%20Eqn%5C%201%5C%5Cw%20%3D%202b-30%5C%20%5C%20%5C%20Eqn%5C%202)
Putting w = 2b-30 in equation 1
![2b-30+b = 87\\3b = 87+30\\3b = 117](https://tex.z-dn.net/?f=2b-30%2Bb%20%3D%2087%5C%5C3b%20%3D%2087%2B30%5C%5C3b%20%3D%20117)
Dividing both sides by 3
![\frac{3b}{3} = \frac{117}{3}\\b = 39](https://tex.z-dn.net/?f=%5Cfrac%7B3b%7D%7B3%7D%20%3D%20%5Cfrac%7B117%7D%7B3%7D%5C%5Cb%20%3D%2039)
Putting b=39 in equation 2
![w = 2(39)-30\\w = 78-30\\w = 48](https://tex.z-dn.net/?f=w%20%3D%202%2839%29-30%5C%5Cw%20%3D%2078-30%5C%5Cw%20%3D%2048)
Hence,
Brian has 39 cards and Wesley has 48 cards
Keywords: Linear equations, variables
Learn more about linear equations at:
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Answer:
20%
Step-by-step explanation:
Add the 3 fractions together.
Mixed fractions: 5 3/4 + 2 2/3 + 10 1/6
Convert to improper fractions and then add. Or simply use a calculator.
Total = 223/12 = 18 7/12
Because infedecimals. Basically 1 -.99999.... Is a number so close to zero it is impossible to define. If this were infanct the case however and a number existed that was not 0 and not 0 it would wreck mathematics so infedecimals exist only theoretically. So .999... Is equal to 1 practically but not theoretically.