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exis [7]
4 years ago
9

Anybody can answer for me please

Mathematics
2 answers:
Romashka [77]4 years ago
8 0
In a triangle, the angle with the smallest measure is always opposite the shortest side.

Further, the angle with the largest measure is always opposite the longest side, and the angle with the second-largest measure is always opposite the second-longest side.

The answer is option B - shortest side.
vladimir2022 [97]4 years ago
3 0
The answer is B 
The shortest side
Hope this helped!
~Melany~ 
;)

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Write a function rule that represents the situation.
Helen [10]

Answer:

i will

Step-by-step explanation:

8 0
3 years ago
How do you find a variable to 4-2(v+9)=26
garik1379 [7]

Answer:

V=20

Step-by-step explanation:

Simplify both sides of the equation.

4−2(v+9)=26

4+(−2)(v)+(−2)(9)=26(Distribute)

4+−2v+−18=26

(−2v)+(4+−18)=26(Combine Like Terms)

−2v+−14=26

−2v−14=26

Step 2: Add 14 to both sides.

−2v−14+14=26+14

−2v=40

Step 3: Divide both sides by -2.

−2v

−2

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40

−2

v=−20

7 0
3 years ago
Wha is 3/8×5/6 you will need a paper.
icang [17]
3/8 x 5/6 = 15/48 = 5/16
4 0
3 years ago
Read 2 more answers
Please Help!! <br> I really need to pass
sesenic [268]

Answer:

None of these

Step-by-step explanation:

The lines aren't parallels so none of these property's can be applied

5 0
3 years ago
Read 2 more answers
Determine whether the following lines represented by the vector equations below intersect, are parallel, are skew, or are identi
KiRa [710]

Answer:

r(t) and s(t) are parallel.

Step-by-step explanation:

Given that :

the  lines represented by the vector equations are:

r(t)=⟨1−t,3+2t,−3t⟩

s(t)=⟨2t,−3−4t,3+6t⟩

The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.

NOTE:

Two lines will be parallel if \dfrac{x_1}{x_2}= \dfrac{y_1}{y_2}= \dfrac{z_1}{z_2}

here;

d_1 = (-1, \ 2, \ -3)

Thus;

r(t) = \dfrac{x-1}{-1} = \dfrac{y-3}{2}=\dfrac{z-0}{-3} = t

d_2 =(2, \ -4, \  +6)

s(t) = \dfrac{x-0}{2} = \dfrac{y+5}{-4}=\dfrac{z-3}{6} = t

∴

\dfrac{d_1}{d_2}= \dfrac{-1}{2} = \dfrac{2}{-4}= \dfrac{-3}{-6}

Hence, we can conclude that r(t) and s(t) are parallel.

6 0
3 years ago
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