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3 years ago

What is the unit value of 3 in 432?

Mathematics

2 answers:

arsen [322]3 years ago

8 0

The answer is ten place :)

vaieri [72.5K]3 years ago

6 0

Its in the tens place so the unit value is 30

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Serggg [28]

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2 years ago

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timofeeve [1]

16. M = 1/5

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2 years ago

If the length of the longest side of a right triangle is 10 inches is 60 degrees, what is the length (in inches) of the shortest

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3 years ago

Lexi asked 325 students which fruit they preferred, bananas or pineapples. 200 students said they preferred pineapples. What per

Serjik [45]

Answer:

38.46%

Step-by-step explanation:

Given,

The total number of students = 325

The number of students preferred pineapples = 200

Therefore, The number of students preferred bananas = (325 - 200) = 125

Among 325 students, banana is preferred 125 students

Among 1 student, banana is preferred 125/325 students

Among 100 students, banana is preferred (125*100)/325 students

= 500/13

= 38.46% (2 decimal places)

5 0

3 years ago

The American Association of Individual Investors conducts a weekly survey of its members to measure the percent who are bullish,

vredina [299]

Answer:

1. There is not enough evidence to support the claim that bullish sentiment differs from its long-term average of 0.39.

2. There is enough evidence to support the claim that bearish sentiment is above its long-term average of 0.30.

Step-by-step explanation:

The question is incomplete:

The American Association of Individual Investors conducts a weekly survey of its members to measure the percent who are bullish, bearish, and neutral on the stock market for the next six months. For the week ending November 7, 2012 the survey results showed 38.5% bullish, 21.6% neutral, and 39.9% bearish (AAII website, November 12, 2012). Assume these results are based on a sample of 300 AAII members.

1. This is a hypothesis test for a proportion.

The claim is that bullish sentiment differs from its long-term average of 0.39.

Then, the null and alternative hypothesis are:

$H_0: \pi=0.39\\\\H_a:\pi\neq 0.39$

The significance level is 0.05.

The sample has a size n=300.

The sample proportion is p=0.385.

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.39*0.61}{300}}\\\\\\ \sigma_p=\sqrt{0.000793}=0.028$

Then, we can calculate the z-statistic as:

$z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.385-0.39+0.5/300}{0.028}=\dfrac{-0.003}{0.028}=-0.118$

This test is a two-tailed test, so the P-value for this test is calculated as:

$P-value=2\cdot P(z$

As the P-value (0.906) is greater than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that bullish sentiment differs from its long-term average of 0.39.

2) This is a hypothesis test for a proportion.

The claim is that bearish sentiment is above its long-term average of 0.30.

Then, the null and alternative hypothesis are:

$H_0: \pi=0.3\\\\H_a:\pi\neq 0.3$

The significance level is 0.05.

The sample has a size n=300.

The sample proportion is p=0.399.

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.3*0.7}{300}}\\\\\\ \sigma_p=\sqrt{0.0007}=0.026$

Then, we can calculate the z-statistic as:

$z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.399-0.3-0.5/300}{0.026}=\dfrac{0.097}{0.026}=3.679$

This test is a two-tailed test, so the P-value for this test is calculated as:

$P-value=2\cdot P(z>3.679)=0$

As the P-value (0) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that bearish sentiment is above its long-term average of 0.30.

3 0

3 years ago