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zimovet [89]
3 years ago
12

1.Simplify negative 7 and 1 over 8 − negative 9 and 1 over 2.

Mathematics
1 answer:
balandron [24]3 years ago
8 0

Answer:

answer is D : 2 3/8

Step-by-step explanation:

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Please help me answer this for me please
slamgirl [31]

Answer:

first one is 5.8

second on is 4.47 round

third one is 1.92

Step-by-step explanation:

8 0
2 years ago
GreenBeam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a m
Harrizon [31]

Answer:

(a) Null Hypothesis, H_0 : \mu \leq 3.50 mg  

     Alternate Hypothesis, H_A : \mu > 3.50 mg

(b) The value of z test statistics is 2.50.

(c) We conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

(d) The p-value is 0.0062.

Step-by-step explanation:

We are given that Green Beam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a mean of 3.59 mg of mercury. Assuming a known standard deviation of 0.18 mg.

<u><em /></u>

<u><em>Let </em></u>\mu<u><em> = average mg of mercury in compact fluorescent bulbs.</em></u>

So, Null Hypothesis, H_0 : \mu \leq 3.50 mg     {means that the average mg of mercury in compact fluorescent bulbs is no more than 3.50 mg}

Alternate Hypothesis, H_A : \mu > 3.50 mg     {means that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg}

The test statistics that would be used here <u>One-sample z test</u> <u>statistics</u> as we know about the population standard deviation;

                          T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean mg of mercury = 3.59

            \sigma = population standard deviation = 0.18 mg

            n = sample of bulbs = 25

So, <em><u>test statistics</u></em>  =  \frac{3.59-3.50}{\frac{0.18}{\sqrt{25} } }

                               =  2.50

The value of z test statistics is 2.50.

<u>Now, P-value of the test statistics is given by;</u>

         P-value = P(Z > 2.50) = 1 - P(Z \leq 2.50)

                                             = 1 - 0.9938 = 0.0062

<em />

<em>Now, at 0.01 significance level the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

6 0
3 years ago
Partial quotient for 350divide 5
azamat

In quotient your answer would be 70

5 0
3 years ago
Hello I need help with my math homework that I don’t understand if you could help me out the would be great thank you
Klio2033 [76]

Answer:

3) 10

4) 12

hope that helps buddy

Step-by-step explanation:


4 0
3 years ago
Anne,Ryan and Joel collect empty cans for recycling. They collect a total of 1,925 cans. Anne collects half as many cans as Ryan
elixir [45]
A + R + J = 1925
A = 1/2R
J = 2R

1/2R + R + 2R = 1925
7/2R = 1925
R = 550

J = 2(550)
J = 1100

Joel collects 1100 cans.
3 0
2 years ago
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